4-03 - 4-3. A gas mixture contains the following quantities...

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Unformatted text preview: 4-3. A gas mixture contains the following quantities per cubic meter of carbon monoxide, carbon dioxide and hydrogen: carbon monoxide, 0.5 moles/m3, carbon dioxide, 0.5 moles/m3, and hydrogen, 0.6 moles/m3. Determine the species mass density and mass fraction of each of the components in the mixture. 4-3. With the given data, the species mass density can be calculated as follows: kg mo l Kg ρ ( 3 )= ρ , ( 3 )× M W ( )V(m 3 ) m m mo l Then, for each species: kg 0.5( 3 )×0.02801( )1(m3 ) Kg CO ρ CO ( 3 )= m 1(m3 ) mol = 0.014 m m3 0.5( mol Kg )×0.044( )1 (m 3 ) 3 Kg CO 2 m mo l = 0.022 3 1(m ) m3 mol Kg (1) ρ CO2 ( kg )= m3 kg ρ H 2 ( 3 )= m 0.6( mol Kg )×0.002( )1(m 3 ) 3 Kg H 2 m mo l = 0.0012 3 1(m ) m3 The total density is determined by ρ = ρ CO + ρ CO Then ρ = 0.0372 kg / m3 2 + ρH 2 (2) and the mass fractions are determined by ω CO Then, = ρ CO /ρ , ω CO 2 = ρ CO /ρ , 2 ωH 2 = ρ H /ρ 2 ω CO = 0.014 /0.0372=0.3763 ω CO =0.022/0.0372=0.5914 2 ωC =0.012/0.0372=0.0323 ...
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This note was uploaded on 07/15/2010 for the course ECM 051 taught by Professor B.g.higgins during the Winter '10 term at UC Davis.

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4-03 - 4-3. A gas mixture contains the following quantities...

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