4-04 - 4-4. The species mass densities of a three component...

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4-4. The species mass densities of a three component liquid mixture are: acetone, , acetic acid, , and ethanol, ρ= . Determine he following for this mixture: 3 326.4 kg/m A 3 326.4kg/m AA 3 217.6 kg/m EA t 1. The mass fraction of each species in the mixture. 2 The mole fraction of each species in the mixture. 3. The mass of each component required to make one cubic meter of mixture. 4-4. The mass fractions are determined by (1) /, / A A AA EA EA AA ω= ρρ ω = E A g g g The total density is determined by (2) AA A ρ = ρ + ρ + ρ and use of the appropriate values leads to (3) 3 ρ = 870.4 kg/m On the basis of Eqs. 1 we have (4) A AA EA ω = 326.4 /870.4 = 0.375 ω = 326.4/870.4 = 0.375 ω = 217.6/870.4 = 0.250 2. The molar fraction can be calculated considering 100 kg of mixture. Then, the amount

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This note was uploaded on 07/15/2010 for the course ECM 051 taught by Professor B.g.higgins during the Winter '10 term at UC Davis.

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4-04 - 4-4. The species mass densities of a three component...

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