Chapter 3B-Stoichiometry TAVSS

Chapter 3B-Stoichiometry TAVSS - CHEM 161-2007 CHAPTER 3B -...

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CHEM 161-2007 CHAPTER 3B - STOICHIOMETRY PRACTICE PROBLEMS DR. ED TAVSS Balancing chemical reactions Reaction stoichiometry Solution Conc.: Molarity Limit. reactants & % yield
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BALANCING CHEMICAL REACTIONS 10 Chem 161-2006 Exam I Hill, Petrucci et al., 4 th edition Chapter 3 – Stoichiometry: Chemical Calculations Balancing chemical equations In the combustion of hexane, C 6 H 14 , reacts with O 2 to produce carbon dioxide and water. How many moles of O 2 are required to react with 1.0 mole of hexane? A . 9.5 B. 19 C. 9 D. 9 E. 3 C 6 H 14 + O 2 → CO 2 + H 2 O C 6 H 14 + O 2 → 6CO 2 + H 2 O C 6 H 14 + O 2 → 6CO 2 + 7H 2 O C 6 H 14 + 19/2 O 2 → 6CO 2 + 7H 2 O 2C 6 H 14 + 19O 2 → 12CO 2 + 14H 2 O A 14. Chem 161-2004 Exam I Zumdahl 6 th edition Chapter 3 Balancing Chemical Equations Consider the reaction
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wPCl 5 + xH 2 O yPOCl 3 + zHCl This equation is balanced when A. choose this choice if none of the others is correct B . w = 1, x = 1, y = 1, z = 2 C. w = 2, x = 2, y = 2, z = 1 D. w = 2, x = 2, y = 2, z = 2 E. w =1, x =2, y = 2, z = 4 wPCl 5 + xH 2 O yPOCl 3 + zHCl Begin with the most complex molecule, which is either PCl5 or POCl3. The P’s are already balanced. Balance the Cl’s. The coefficient to balance the Cl’s must go on the HCl because if the coefficient goes on the POCl3 then the P’s will no longer be balanced. PCl 5 + H 2 O POCl 3 + 2HCl Everything is now balanced. ZUMDAHL 5 TH EDITION CHEM 161-2002 RECITATION 4 TH WEEK CHAPTER 3 - STOICHIOMETRY BALANCING CHEMICAL REACTIONS 3-83 Balance the following equations representing combustion reactions: a. C 12 H 22 O 11(s) + O 2(g) → CO 2(g) + H 2 O (g) a. C 12 H 22 O 11(s) + 12O 2(g) → 12CO 2(g) + 11H 2 O (g) b. C 6 H 6(l) + O 2(g) → CO 2(g) + H 2 O (g) b. C 6 H 6(l) + (15/2)O 2(g) → 6CO 2(g) + 3H 2 O (g) b. 2C 6 H 6(l) + 15O 2(g) → 12CO 2(g) + 6H 2 O (g) c. 2Fe (s) + (3/2)O 2(g) → Fe 2 O 3(s)
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c. 4Fe (s) + 3O 2(g) → 2Fe 2 O 3(s) d. C 4 H 10(g) + O 2(g) → CO 2(g) + H 2 O (g) d. C 4 H 10(g) + (13/2)O 2(g) → 4CO 2(g) + 5H 2 O (g) d. 2C 4 H 10(g) + 13O 2(g) → 8CO 2(g) + 10H 2 O (g) e. FeO (s) + O 2(g) → Fe 2 O 3(s) e. 2FeO (s) + (1/2)O 2(g) → Fe 2 O 3(s) e. 4FeO (s) + O 2(g) → 2Fe 2 O 3(s)
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CHEM 161-1999 FINAL EXAM + ANSWERS CHAPTER 3 - STOICHIOMETRY BALANCING CHEMICAL EQUATIONS 3. When the following equation is balanced using the smallest integers, the coefficient of BCl 3 is: BCl 3 + P 4 + H 2 -> BP + HCl A. 1 B. 2 C. 3 D . 4 E. 5 18. CHEM 161-2000 EXAM I ZUMDAHL CHAPTER 3 - STOICHIOMETRY BALANCING CHEMICAL EQUATIONS What is the coefficient of Fe 3 O 4 when the following equation is balanced? Al + Fe 3 O 4 Al 2 O 3 + Fe A. 2 B . 3 C. 4 D. 5 E. 1 CHEM 161-2001 FINAL EXAM WITH ANSWERS CHAPTER 3 - STOICHIOMETRY BALANCING CHEMICAL EQUATIONS 16. When the following equation is balanced, the coefficient of H 2 O is: SiCl 4 + H 2 O → SiO 2 + HCl A .2 B.5 C.1 D.4 E.3 SiCl 4 + 2H 2 O -> SiO 2 + 4 HCl CHEM 161-2001 SUMMER FINAL EXAM + ANSWERS
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This note was uploaded on 07/17/2010 for the course 160 162 taught by Professor Kimmel during the Spring '10 term at Rutgers.

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Chapter 3B-Stoichiometry TAVSS - CHEM 161-2007 CHAPTER 3B -...

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