SmithExam1 - 18-4.35 18.92 17-5.35 28.62 17-5.35 28.62...

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Olivia Smith_x000D_ Ages of the Dancers 35 27 26 26 25 25 25 25 23 22 21 21 20 19 19 19 18 17 17 17 22.35 21.5 25 18 25 4.5 20.24 There would be eleven bars on the graph because there are twenty dancers but some of them have the s  they would be grouped within one bar. (19,19,19,35,27) being represented in the problem 20/5=4. 21.5 19 x x-22.35 (x-22.35)^2 35 12.65 160.02 27 4.65 21.62 26 3.65 13.32 Age groups Frequency 26 3.65 13.32 17-21 5 25 2.65 7.02 22-26 6 25 2.65 7.02 27-31 1 25 2.65 7.02 32-36 1 25 2.65 7.02 There is only one data in the third class  23 0.65 0.42 only one dancer's age was within that gr 22 -0.35 0.12  classes have a class width of five. 21 -1.35 1.82 21 -1.35 1.82 20 -2.35 5.52 35 27 26 26 25 25 25 25 23 22 21 21 20 19 19 19 18 17 17 17 Ages of the Dancers
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Olivia Smith_x000D_ 19 -3.35 11.22 19 -3.35 11.22 19 -3.35 11.22
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Unformatted text preview: 18-4.35 18.92 17-5.35 28.62 17-5.35 28.62 17-5.35 28.62 TOTAL 384.55 Variance based on chart: 18.23 Standard Deviation Base 4.27 18.08 26.62 The standard deviation is 19.7% of the mean. Based on all of these calculations I would use Chebyshev's Theorem to describe the distribution of the da 93% of the dancer's ages lie within 4 standard deviations of the mean. The Emperical formula wouldn't w the graph doesn't show a bell shaped curve AND the ages don't follow the 68-95-99 pattern. Approximately 49% of the ages of the dancers is set within one standard deviations of the mean. Olivia Smith_x000D_ same ages, e values: (27-31) because roup if each of the Olivia Smith_x000D_ ata because ork here because...
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SmithExam1 - 18-4.35 18.92 17-5.35 28.62 17-5.35 28.62...

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