# SmithExam2 - OliviaSmith x P(x) x*P(x) (xmu)^2*P(x) 0.06...

This preview shows pages 1–2. Sign up to view the full content.

x P(x) x*P(x) (x-mu)^2*P(x) 0 0.02 0 0.06 1 0.28 0.28 0.17 2 0.61 1.22 0.03 3 0.09 0.27 0.14 1.77 0.4 Mean = 1.77 Variance= 0.4 Standard Deviation= 0.63 a) Exactly 3 refrigerators is:  0.09 b) At least two refrigerators is:  0.7 c) Fewer than 3 refrigerators is: 0.91 d) The mean of the distribution is: 1.77 e) The standard deviation is: 0.63 x P(x) x*P(x) (x-mu)^2*P(x) 0 0.248423 0 1 0.371207 0.371 0.03 2 0.249605 0.499 0.12 3 0.099459 0.298 0.29 4 0.026008 0.104 0.19 5 0.004664 0.023 0.06 6 0.000581 0.003 0.012827799 7 0.000050 0.000 0 8 0.000003 0.000 0 9 0.000000 0.000  0.000005470  10 0.000000 0.000  0.00000010  1.300 0.71  Mean=   1.30  Variance= 0.711164 Standard Deviation= 0.843306 a) Exactly 2 become delinquent: P(2): 0.249605 b) 3 or 4 become delinquent: 0.125468 c) 1 becomes delinquent: 0.371207 d) The mean of the distribution is: 1.300000 e) The standard deviation is: 0.843306 x P(x) x*P(x) (x-mu)^2*P(x) 0 0.000002 0.000

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 07/20/2010 for the course MATH 251 taught by Professor Whalen during the Summer '10 term at New Hampshire Community Technical Colleges.

### Page1 / 3

SmithExam2 - OliviaSmith x P(x) x*P(x) (xmu)^2*P(x) 0.06...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online