hw5soln

hw5soln - Prof. Parker 1) 1-a) Homework Assignment #5...

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Prof. Parker Homework Assignment #5 Solution EE 477 Fall 2008 1) 1-a) β n =4.3 β p and the NMOS transistors are unit size transistor so we have W n =4 λ and L n =2 λ and we take L p =L n =2 λ β neff = β n β peff = β p = ଻כସ.ଷ β n At the worst case rise and fall time we want: rise time = 2*fall time Î R eff (pull up) = 2*R eff (pull down) Î 2* β peff = β neff 2 ଻כସ.ଷ β n = β n Î W p =15.05 W n =15.05 (4 λ )=60.2 λ (60 λ is used) 1-b)
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2) β n =4.3 β p and for the smallest transistor (PMOS) we have W p =8 λ and L p =2 λ and we take L p =L n =2 λ β neff = β n β peff = β p = ସ.ଷ β n β peff = β neff Î β n = ସ.ଷ β n Î W n =1.16 W p =1.16 (8 λ )=9.3 λ (9 λ is used) Worst case fall happens we go from ABCDE=1110 to 11111 and worst case rise happens when
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hw5soln - Prof. Parker 1) 1-a) Homework Assignment #5...

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