Chm 139 Chapter Notes pg.3 - Molarity M: The number of...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Molarity M: The number of moles of the solute dissolved in a liter of solution. the final volume of the solution is important, not the initial volume of the solvent. Moles of solute =Mi *Vi = Mf *Vf ( moles of solute= initial consentration * initial volume. Moles of solute is also equal to final consentration * final volume. This happens because the number of moles in the solute never changes just because you add more water. It is a constant number. When the volume of a solution increases, the concentration of the solute desecrates proportionally. Neutralization: with acid and base reactions, it just what they call the reaction Titration: the process of finding the unknown concentration of a solution with a kown volume by allowing it to react with a solution with a known concentration^-1n (and later known vlume) to react with it until the reaction has gone to completion. When ther reaction has finished, you then reading out how much of the known concentration solution reacted with the unknown solution you can find the second ones concentration. Percent composition:
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/22/2010 for the course CHM CHM139H1 taught by Professor Browning during the Fall '08 term at University of Toronto- Toronto.

Ask a homework question - tutors are online