mech_hw_solutionsv2a

# mech_hw_solutionsv2a - Mechanism Homework Solutions ME 350...

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Mechanism Homework Solutions ME 350: Fall 200 ! Problem 1: Slides will differ between students. One typical example will be a piston. System should be a closed loop sys- tem.

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trans = | i 4 - i 3 | -100 -80 -60 -40 -20 0 20 40 60 80 100 0 50 100 150 200 250 300 350 400 θ 2 (degrees) θ 3 , 4 , trans angles (degrees) θ 4 θ 3 trans

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0 50 100 150 200 250 300 350 400 10 20 30 40 50 d (mm) 160 180 200 220 240 Piston and Angular Displacement θ 2 (degrees) θ 3 (degrees)
W 1 x =- 86.62; W 1 y = 50.03; Z 1 x = 198.15; Z 1 y 233.31 w = 100.03; z = 306.1; z 0.87 rads ( - 49.66 c ) U 1 x = 107.55; U 1 y = 205.37; S 1 x = 3.37; S 1 y 166.93 u = 231.82; v = 1.09 rads (62.36 c ) s = 166.96; } 1.55 rads ( - 88.84 c )

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W 2 + Z 2 - P 21 1 1 = 0 W 3 + Z 3 - P 31 - Z 1 - W 1 = 0 we j ( i + b 2 ) + ze j ( z + a 2 ) - p 21 e j d 2 - ze j z - we j i = 0 we j ( i + b 3 ) + ze j ( z + a 3 ) - p 31 e j d 3 - ze j z - we j i = 0 we j i e j b 2 + ze j z e j a 2 - p 21 e j d 2 - ze j z - we j i = 0 we j i e j b 3 + ze j z e j a 3 - p 31 e j d 3 - ze j z - we j i = 0 we j i ( e j b 2 - 1) + ze j z ( e j a 2 - 1) = p 21 e j d 2 we j i ( e j b 3 - 1) + ze j z ( e j a 3 - 1) = p 31 e j d 3 e ! j i = cos i ! j sin i w (cos i + j sin i )((cos b 2 + j sin b 2 ) - 1) + z (cos z + j sin z )((cos a 2 + j sin a 2 ) - 1) = p 21 (cos d 2 + j sin d 2 ) w (cos i + j sin i )((cos b 3 + j sin b 3 ) - 1) + z (cos z + j sin z
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## This note was uploaded on 07/22/2010 for the course ME Mecheng 35 taught by Professor 350 during the Winter '08 term at University of Michigan-Dearborn.

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mech_hw_solutionsv2a - Mechanism Homework Solutions ME 350...

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