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Unformatted text preview: reyes (mr29667) – Homework 10 – chelikowsky – (59005) 1 This printout should have 7 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points At t = 0, a wheel rotating about a fixed axis at a constant angular deceleration of 0 . 65 rad / s 2 has an angular velocity of 1 . 7 rad / s and an angular position of 6 . 3 rad. What is the angular position of the wheel after 5 s? Correct answer: 6 . 675 rad. Explanation: Let : α = − . 65 rad / s 2 , ω = 1 . 7 rad / s , θ = 6 . 3 rad , and t = 5 s . The angular position is θ f = θ + ω t + 1 2 αt 2 = 6 . 3 rad + (1 . 7 rad / s) (5 s) + 1 2 ( − . 65 rad / s 2 ) (5 s) 2 = 6 . 675 rad . 002 (part 1 of 3) 10.0 points As a result of friction, the angular speed of a wheel c hanges with time according to d θ d t = ω e σ t , where ω and σ are constants. The angular speed changes from an initial angular speed of 5 . 31 rad / s to 4 . 21 rad / s in 3 . 92 s . Determine the magnitude of the angular acceleration after 2 . 45 s. Correct answer: 0 . 271976 rad / s 2 ....
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This note was uploaded on 07/24/2010 for the course PHY 59005 taught by Professor Chelikowsky during the Fall '09 term at University of Texas at Austin.
 Fall '09
 Chelikowsky

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