This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: reyes (mr29667) Homework 12 chelikowsky (59005) 1 This printout should have 18 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points Assume: A bullet of mass m and cube of mass M undergo an inelastic collision, where m M . Note: The moment of inertia of this cube (with edges of length 2 a and mass M ) about an axis along one of its edges is 8 M a 2 3 . A solid cube is resting on a horizontal sur face. The cube is constrained to rotate about an axis at its bottom right edge (due to a small obstacle on the table). A bullet with speed v min is shot at the lefthand face at a height of 4 3 a . The bullet gets embedded in the cube. 2 a M mvectorv min 4 3 a M g Find the minimum value of v min required to tip the cube so that it falls its righthand face. 1. v min = m M radicalbigg 3 g a parenleftBig 3 1 parenrightBig 2. v min = m M radicalbigg 3 g a parenleftBig 5 1 parenrightBig 3. v min = m M radicalbigg 5 g a parenleftBig 2 1 parenrightBig 4. v min = M m radicalbigg 3 g a parenleftBig 2 1 parenrightBig correct 5. v min = m M radicalbigg 2 g a parenleftBig 2 1 parenrightBig Explanation: Basic Concepts: summationdisplay vector L = const U + K = 0 For the cube to tip over the center of mass (CM) must rise so that it is over the axis of rotation AB . To do this the CM must be raised a distance of a parenleftBig 2 1 parenrightBig . From conservation of energy M g a parenleftBig 2 1 parenrightBig = 1 2 I cube 2 . (1) From conservation of angular momentum 4 a 3 mv = parenleftbigg 8 M a 2 3 parenrightbigg = parenleftBig mv 2 M a parenrightBig . (2) Thus, substituting Eq. 2 into 1, we have 1 2 parenleftbigg 8 M a 2 3 parenrightbiggparenleftbigg m 2 v 2 4 M 2 a 2 parenrightbigg = M g a parenleftBig 2 1 parenrightBig Solving for v yields v min = M m radicalbigg 3 g a parenleftBig 2 1 parenrightBig . 002 10.0 points If you walk along the top of a fence, why does holding your arms out help you to balance? 1. Your momentum is increased. 2. Your rotational inertia is decreased. 3. Your momentum is decreased. 4. Your rotational inertia is increased. cor rect Explanation: Your rotational inertia increases when your arms are outstretched, which increases the resistance to a change in your rotational state. 003 10.0 points The angle of the inclination is 36 . 6 , the outer part of the large pulley has a radius of 3 r and the inner part of the large pulley has a radius of r . reyes (mr29667) Homework 12 chelikowsky (59005) 2 3 r r /2 r m T Find the mass m needed to balance the 1780 kg truck on the incline. The acceleration of gravity is 9 . 8 m / s 2 . Assume all pulleys are frictionless and massless and the cords are massless....
View
Full
Document
This note was uploaded on 07/24/2010 for the course PHY 59005 taught by Professor Chelikowsky during the Fall '09 term at University of Texas at Austin.
 Fall '09
 Chelikowsky

Click to edit the document details