solution hw 3 - reyes (mr29667) Homework 3: Ideal gases...

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Unformatted text preview: reyes (mr29667) Homework 3: Ideal gases Shear (52375) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. You may need to look up conversion factors and values of R in the back of your textbook. 001 (part 1 of 3) 10.0 points Methanol (CH 3 OH) is the simplest of the al- cohols. It is synthesized by the reaction of hydrogen and carbon monoxide: CO(g) + 2 H 2 (g)- CH 3 OH If 580 mol of CO and 284 mol of H 2 are present, which is the limiting reactant? 1. CO 2. H 2 correct Explanation: n CO = 580 mol n H 2 = 284 mol limiting reactant = ? mole ratio : 2 mol H 2 1 mol CO . n H 2 required = 580 molCO 2 mol H 2 1 mol CO = 1160 mol H 2 Because there is only 284 mol H 2 available, the limiting reactant is H 2 . 002 (part 2 of 3) 10.0 points How much of the excess reactant remains un- changed? Correct answer: 438 mol. Explanation: remaining excess reactant = ? n CO reacting = 1 mol CO 2 mol H 2 284 mol H 2 = 142 mol CO n excessreactant = 580 mol CO- 142 mol CO = 438 mol CO 003 (part 3 of 3) 10.0 points How much CH 3 OH is formed? Correct answer: 142 mol. Explanation: n limiting reactant = 284 mol H 2 amounts of CH 3 OH = ? mole ratio : 1 mol CH 3 OH 2 mol H 2 n CH 3 OH = 1 mol CH 3 OH 2 mol H 2 284 mol H 2 = 142 mol CH 3 OH 004 10.0 points Helium is used to inflate football-shaped bal- loons that will be released in Memorial sta- dium for the opening game of the football season.season....
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This note was uploaded on 07/24/2010 for the course CH 52375 taught by Professor Ruth during the Spring '09 term at University of Texas at Austin.

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solution hw 3 - reyes (mr29667) Homework 3: Ideal gases...

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