Module 5

# Module 5 - Module 5 1 Post the problems you will have in...

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Module 5 . 1 Post the problems you will have in your problem set ASAP so no other student will . select the problem . 2 , . If you have trouble with the problem post your question on the discussion Cafe You will not be able to see other postings on your problems until you have posted your . solutions , You must state which problem you are doing you may have to include a - - free body diagram or other diagram if it helps your . discussion You must show units and . explain each step The format that is used in the text book is similar to the way . you will discuss the problem . 3 , If you have problems with the problem you will have the opportunity to ask the . group for help Other class members will have the opportunity to help with the . problem and earn some points . 4 . You must critique your classmate's work ( " " .) Saying good job is not appropriate . You cannot fall behind in class Module 5 covers chapters 11 and . 12 : Chapter : 11 . 5 The karat is a dimensionless unit that is used to indicate the proportion of gold - . in a gold containing alloy An alloy that is one karat gold contains a weight of pure . gold that is one part in 24 . - . What is the volume of gold in a 14 0 karat gold necklace whose weight is 1 27 N? : Mass of gold alloy = = = W mg Wg m . . / ≈ . 1 27 N9 80 m s2 0 1296 kg : Volume of gold alloy = = = ρ mV mρ V . . / ≈ . - = . 0 1296 kg19 3 x 103 kg m3 6 7146 x 10 6 m3 6 7146 cm3 : Volume of pure gold in alloy . ≈ . = . 14246 7146 cm3 3 91685 cm3 3 92 cm3 . 13 ( . Interactive solution 11 13 at . . / / www wiley com college cutnell is a model for this ). . problem A solid concrete block weighs 169 N and is resting on the ground Its . . . . dimensions are 0 400 m x 0 200 m x 0 100 m A number of identical blocks are . stacked on top of this one

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( ) What is the smallest number of whole blocks including the one on the ground that can be stacked so that their weight creates a pressure of at least two atmospheres on the ground beneath the first block? = P FA = . * . = . A 0 200m 0 100 m 0 02 m2 = . 1 atm 1 013 x 105Pa = + . 2 atm n 1169 N0 02 m2 + = * . . = . . = . n 1 2 1 013 x 105Pa0 02 m2169 N 2 026 x 105 Pa0 02 m2169 N 4 052 x 103 / . Pa m2169 N 23 976 + = . n 1 23 976 = n 23 23 whole blocks will create 2 atmospheres of pressure on the ground beneith the first block : INSTRUCTORS NOTES
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Module 5 - Module 5 1 Post the problems you will have in...

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