This preview shows page 1. Sign up to view the full content.
Unformatted text preview: y . i. Since z = x + iy , ( iz + 2) = 2y . Thus ( iz + 2) > 0, means 2 > y , so we are left with the part of the plane below the line y = 2. 3. Letting a = u + iv , and z = x + iy as usual, we have  z  22 ( az ) +  a  2 = x 2 + y 22 (( uiv )( x + iy )) + u 2 + v 2 = x 2 + y 22 ( ux + vy + i ( uyvx )) + u 2 + v 2 = x 2 + y 22( ux + vy ) + u 2 + v 2 = ( xu ) 2 + ( yv ) 2 . 1...
View
Full
Document
This note was uploaded on 07/27/2010 for the course MATH Math2009 taught by Professor Koskesh during the Spring '09 term at SUNY Empire State.
 Spring '09
 Koskesh
 Math

Click to edit the document details