FLUID MECHANICS PROBLEMS I SOLUTIONS

FLUID MECHANICS PROBLEMS I SOLUTIONS - FLUID MECHANICS...

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Unformatted text preview: FLUID MECHANICS PROBLEMS I SOLUTIONS 1) a) The buoyant force provides the upwards thrust that essentially reduces the weight of the object. Hence, ( 29 F N F N B B =- = 30 14 16 . . . . b) ( 29 ( 29 ( 29 ( 29 F V g N kg m V m s V m B water water water water = = = - 16 10 9 8 163 10 3 3 2 4 3 . . . . c) Since the plastic toy is under water, then the volume of the toy is equivalent to the volume of displaced fluid. Thus, V V m water plastic = = - 163 10 4 3 . . Neglecting the buoyant force due to air, the mass of the plastic toy is m N ms m kg plastic plastic = = -- 3 9 8 306 10 2 1 . . . Hence, the density of the plastic toy is plastic plastic plastic m V = = =-- plastic plastic kg m kg m 306 10 163 10 1877 1 4 3 . . 3 . 2) a) V m V kg kg m V m stone stone stone stone stone = = = - 24 2500 9 6 10 3 3 3 . . b) ( 29 ( 29 F kg ms F N g g = =- 24 9 8 2352 2 . . . c) ( 29 ( 29 ( 29 ( 29 F V g F kg m m m s F N B water water B B = = =- 1000 9 6 10 9 8 941 3 3 2 3 . . . . d) In order to lift the stone, the boy must supply the difference between the weight of the stone and the buoyant force. Hence, the boy must supply ( 29 F N F N applied applied =- = 2352 941 1411 . . ....
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FLUID MECHANICS PROBLEMS I SOLUTIONS - FLUID MECHANICS...

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