Meen 222- Quiz 2a

# Meen 222- Quiz 2a - u=1/3(2u’-v’)=1 v=1/3(2v’-u’)=0...

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Max von Laue (October 9, 1879 in Pfaffendorf, Germany - April 24, 1960 in Berlin, Germany) was a German physicist From 1919 von Laue was a professor of theoretical physics at the University of Berlin. He worked out a method for measuring X-ray wavelengths, in which a crystal (e.g. rock salt) is used, producing diffraction of the rays. For this work, which also made possible a closer study of crystal structure (a method called X-ray crystallography), he received the 1914 Nobel Prize in Physics. His discovery enabled scientists to study the structure of crystals. MEEN 222 – 503 Fall 2008 Quiz #2A Student: Print First and Last Name

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1. Determine the indices for the directions and planes shown in following unit cells: ½ 1 ½ X2 ½ -1 reciprocal [121] (021) ) u’=1; v’=1/2; w’=0 x2 -1 1 reciprocal u’=2; v’=1; w’=0
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Unformatted text preview: u=1/3(2u’-v’)=1 v=1/3(2v’-u’)=0 t=-(u+v)=-1 w=w’=0 [1010] (0110) 2. Derive planar density expression for Face Centered Cubic (110) plane in terms of the atomic radius R. Note: Sketch FCC unit cell and (110) plane. Label all relevant distances! PD=(number of atoms per unit area)/(area of the unit area) d=4R=a √ 2 → a =2R/ √ 2 unit area A=d· a =2R·4R/ √ 2 = 8R 2 √ 2 PD= 2 atoms / 8R 2 √ 2 = 1 atom/ 4R 2 √ 2 Diagonal of the cube: 3 a D = a=length of the cube’s edge Diagonal of the square: 2 a d = a=length of the square’s side 1 nm = 10-9 m, 1 m = 10 2 cm N A =6.23 x 10 23 atom/mol 1/2 a a a a a a z z z z x x y y x’ y’ 1 point 1 point 1 point 1 point 1 point a d 1 point for FCC 1 point for (110) 1 point for unit area 1 point for PD 1 point for # of atoms...
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Meen 222- Quiz 2a - u=1/3(2u’-v’)=1 v=1/3(2v’-u’)=0...

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