Meen 315- Lecture 3

Meen 315- Lecture 3 - Lecture 03: Chapter 01: 1.8-1.12(...

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1 Lecture 03: Chapter 01: 1.8-1.12( Contd. .) 1.1 Thermodynamics and Energy 1.2 Dimensions and Units 1.3 Systems : Closed and Open 1.4. Properties 1.5 Density, spec Gravity 1.6 State 1.7 Processes, Cycles 1.8. T, Zeroth law 1.9. Pressure 1.10 Manometer 1.11 Atm Press 1.12 Problem Solving (Skip) Longwood Gardens, Philadelphia, Pa
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2 Meeting Day Date Subject Read 1 T Jan 15 Introduction, conservation of energy, dimensions and units, problem solving, systems 1-1—1-3 2 R Jan 17 Properties, states, equilibrium, processes 1-4—1-7 3 T Jan 22 Temperature, pressure; Communicating equations 1-8—1-12; Notes 4 R Jan 24 Intro to EES, energy, heat, work; Tables and figures Notes, 2-1—2-5 5 T Jan 29 Heat, work, first law of thermodynamics; Abstracts 2-3—2-6; Notes 6 R Jan 31 1 st Law, efficiency, phases, phase changes; Referencing 2-6—2-8, 3-1—3-4; Notes 7 T Feb 5 Property data 3-5 8 R Feb 7 Property equations (of state), boundary work 3-6—3-8, EES, 4-1 9 T Feb 12 Energy balance, spec. heats, internal energy, enthalpy 4-2—4-5 10 R Feb 14 Conservation of mass 5-1 11 T Feb 19 Flow work, steady-flow systems 5-2—5-3 12 R Feb 21 Exam 1, Thurs, 2/21, 7-9 p.m., location TBA Optional review in class 13 T Feb 26 Nozzles, diffusers, turbines, compressors, heat exch. 5-4 14 R Feb 28 Heat exchangers, transient flow 5-4—5-5 15 T Mar 4 Second law of thermo, energy reservoirs, heat engines, heat pumps, refrigerators, reversibility 6-1—6-7
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3 THREE IMPORTANT EQUATIONS Mass Conservation (Chap 1 and 5): First Law or Energy Conservation(Chap 4 and 5) •E cv = U+KE+PE, Second Law or Entropy Balance Equation (Not in Text) cv e exit e e i inlet i i j j b j cv s m s m T Q dt dS σ ± ± ± ± + + = = = , + + Σ + + Σ + = e e e e i i i i cv cv CV gz h m gz h m W Q dt dE 2 V 2 V 2 2 = = = exit e e inlet i i cv m m dt dm ± ±
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4 Announcement Please Sit according to team Seating chart posted on Web
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5 Announcement TEAMS; SEATING CHART posted by Monday; Check web pages Please Sit according to team Seating chart posted on Web
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6 Easy way to get lb f in English Units • You know that 1000 g = 1kg • Similarly when you use Newton’ s law with lb m , ft, s units, F= m ( lbm) * a ( ft/s 2 ), then for 10 lbm accelerating at 16.08 ft/s 2 , F (in lbm/ft s 2 ) = 10 lbm* 16.08 ft/s2= 160.8 lb m ft/s 2 ; just like 1000 g = 1 kg, we will call 32.17 lb m ft/s 2 = 1 lbf. So 160.8 lb m ft/s 2 must be equal to 2 ff 2 f lbm 160.8 ft s F (lb ) 5 lb lbm 32.174 ft s lb == ⎛⎞ ⎜⎟ ⎝⎠
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7 1.6 ( Contd) Simple system and Quasi-equilibrium PdV work dX P •Assume resisting force slightly less than force exerted by fluid •Force by fluid in system = P* A Resisting Force (quasi-equil) •Work, δ W = Resisting force* distance Moved = P* A* dx= P * dV= Pressure * volume change of system A simple system is defined as one for which only one quasi- equilibrium work mode applies.
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This note was uploaded on 07/28/2010 for the course MEEN 315 taught by Professor Ramussen during the Fall '07 term at Texas A&M.

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Meen 315- Lecture 3 - Lecture 03: Chapter 01: 1.8-1.12(...

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