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# Next ii has dimensions of l so it must be the

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Unformatted text preview: ext (ii) has dimensions of L so it must be the circumference, (a). Finally, equation   © © ¦  ¦ ©   © ¦  © ¦ ¦  ¡ ©  ¥ ¢ £ § ¤ ¡ and the mass is given by the relation: m ¡ ¡ ¢ ¤ (6.1) V (6.2) ¥ ¦ © ¢¥ ¢¥ ¥¦ ¥ ¨ ¥ ¢ £ ¢ ¤ (10.2) (iii) has dimensions of L L 2 To sum up our conclusions: (i) <-> (b) (ii) <-> (a) (iii) <->(c) Prob 1.17) To find the units of G we insert the units for the other variables. Force is in Newtons, where N kg m s 2 , masses are in kilograms, and radius is in meters. Using the notation [A] = dimensions of A and plugging these units into the inverse square law yields the foll...
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## This note was uploaded on 07/28/2010 for the course PHYS 207 taught by Professor Winnokur during the Fall '06 term at University of Wisconsin.

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