Unformatted text preview: ext (ii) has dimensions of L so it must be the circumference, (a). Finally, equation © © ¦ ¦ © © ¦ © ¦ ¦ ¡ © ¥ ¢ £ § ¤ ¡ and the mass is given by the relation: m ¡ ¡ ¢ ¤ (6.1) V (6.2) ¥ ¦ © ¢¥ ¢¥ ¥¦ ¥ ¨ ¥ ¢ £ ¢ ¤ (10.2) (iii) has dimensions of L L 2 To sum up our conclusions: (i) <> (b) (ii) <> (a) (iii) <>(c) Prob 1.17) To find the units of G we insert the units for the other variables. Force is in Newtons, where N kg m s 2 , masses are in kilograms, and radius is in meters. Using the notation [A] = dimensions of A and plugging these units into the inverse square law yields the foll...
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This note was uploaded on 07/28/2010 for the course PHYS 207 taught by Professor Winnokur during the Fall '06 term at University of Wisconsin.
 Fall '06
 Winnokur
 Physics, Work

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