Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Physics 207 Homework 1 Solutions Due 9/14/05 Assignment: Ch 1, problems 6, 10, 14, 17, 23, 30, 38, 43, 48, 50 Prob 1.6) The volume of an individual sphere is given by: 4 V r3 3 If we substitute equation 1 into 2 we find that: 4 m r3 (6.3) 3 Now, dividing equation 6.3 for the large sphere by equation 3 for the small sphere and using that the ratio of large mass to small mass is five gives the following: 4 r3 large mlarge r3 3 large 5 (6.5) 3 m small 4 r small 3 r small 3 Multiplying by the cube of the small radius and taking the cube root gives us the answer: r large 3 r small (6.6) Prob 1.10) (a) The volume of a cube is given by the cube of the length so the mass is given by the density times the length cubed: m V L 3 7.8...
View Full Document

This note was uploaded on 07/28/2010 for the course PHYS 207 taught by Professor Winnokur during the Fall '06 term at University of Wisconsin.

Ask a homework question - tutors are online