Chapter10 - Chapter 10 Analog Systems Microelectronic Circuit Design Richard C Jaeger Travis N Blalock Jaeger\/Blalock Microelectronic Circuit Design 3E

Chapter10 - Chapter 10 Analog Systems Microelectronic...

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Jaeger/Blalock 6/15/07 Microelectronic Circuit Design, 3EMcGraw-HillChapter 10Analog Systems Microelectronic Circuit DesignRichard C. Jaeger Travis N. BlalockChap10 - 1
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Jaeger/Blalock 6/15/07 Microelectronic Circuit Design, 3EMcGraw-HillChapter Goals Develop understanding of linear amplification concepts such as:Voltage gain, current gain, and power gain Gain conversion to decibel representation Input and output resistances Transfer functions and Bode plots Cutoff frequencies and bandwidth Low-pass, high-pass, band-pass, and band-reject amplifiers Biasing for linear amplification Distortion in amplifiers Two-port representations of amplifiers Use of transfer function analysis in SPICE Chap10 - 2
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Jaeger/Blalock 6/15/07 Microelectronic Circuit Design, 3EMcGraw-HillExample of Analog Electronic System: FM Stereo ReceiverLinear functions: Radio and audio frequency amplification, frequency selection (tuning), impedance matching (75-Ωinput, tailoring audio frequency response, local oscillator Nonlinear functions: DC power supply(rectification), frequency conversion (mixing), detection/demodulationChap10 - 3
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Jaeger/Blalock 6/15/07 Microelectronic Circuit Design, 3EMcGraw-HillAmplification: IntroductionA complex periodic signal can be represented as the sum of many individual sine waves. We consider only one component with amplitude Vs = 1 mV and frequency ωswith 0 phase (signal is used as reference): Amplifier output is sinusoidal with same frequency but different amplitude VOand phase θ: vs=Vssinωstvo=Vo(sinωst+θ)Chap10 - 4
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Jaeger/Blalock 6/15/07 Microelectronic Circuit Design, 3EMcGraw-HillAmplification: Introduction (cont.)Amplifier output power is: Here, PO= 100 W and RL = 8 ΩOutput power also requires output current which is: Input current is given by phase is zero because circuit is purely resistive. PO=Vo2ΛিΝয়Μ৏Μ৏Μ৏Ξ৯ΠਏΟ৿Ο৿Ο৿21RLVo=2PORL=2×100×8=40ViO=Io(sinωst+θ)Io=VoRL=40V8Ω=5AIs=VsRS+Rin=10-3V5kΩ+50kΩ=1.82×108AChap10 - 5
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Jaeger/Blalock 6/15/07 Microelectronic Circuit Design, 3EMcGraw-HillAmplification: GainVoltage Gain: Magnitude and phase of voltage gain are given by and For our example, Current Gain: Magnitude of current gain is given by Av=vOvS=VoθVs0=VoVsθAv=VoVsθ=vAAv=VoVs=40V103V=4×104Ai=iOiS=IoθIs0=IoIsθAi=IoIs=5A1.82×10-8A=2.75×108Chap10 - 6
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Jaeger/Blalock 6/15/07 Microelectronic Circuit Design, 3EMcGraw-HillAmplification: Gain (cont.)Power Gain: For our example, On decibel scale, i.e. in dB AP=POPS=Vo2Io2Vs2Is2=VoVsIoIs=AvAiAP=40×5103×1.82×108=1.10×1013AvdB=20logAvAidB=20logAiAPdB=10logAPChap10 - 7
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Jaeger/Blalock 6/15/07 Microelectronic Circuit Design, 3EMcGraw-HillAmplifier Biasing for Linear OperationvI=VI+viVI = dc value of vI, vi = time-varying component For linear amplification - vI
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