This preview shows page 1. Sign up to view the full content.
Unformatted text preview: ional tolerance assigned by the bearing manufacturer to the width dimension of the bearing, may, or may not, be distinct from tPa, the size tolerance on this same width. For purposes of this sample computation, we set t″Pa = tPa and combine these terms with the one for tw. Then, when the value of tf , the functional tolerance, is normalized to 1mm, each term becomes (1/12)tf = 0.0833mm. The values obtained for the tolerances are shown in Table 1. Although the equality of terms in eqn (2) may or may not give the lowest manufacturing cost, nonetheless, eqn (2) shows the relative importance of all the tolerances in positioning the blade laterally. Equation (3) represents the accumulation of angles (tilt) from the hinge supporting the arm to the saw blade. The accumulated orientational variations, t″a, is calculated by substituting the allocated tolerance values from Table 1 into equation (3), which gives, t″a = (22/2)*(0.016/76.27+0.0053/12.06)+2*0.041+0.51*(5*0.163)+0.0833+2*0.00416 = 0.5964mm This number represents an orientational tolerance-zone of diameter 44mm wh...
View Full Document
This note was uploaded on 08/03/2010 for the course DD 1234 taught by Professor Zczxc during the Spring '10 term at Magnolia Bible.
- Spring '10
- The Land