Bruyere et al deviations on the kinematic error by

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Unformatted text preview: r f(1) (ϕ 0 , θ , φ1 ) ∂θ ⋅ n (f2 ) (α , γ , φ 2 ) = 0 or ∂r f(1) (ϕ 0 , θ , φ1 ) ∂θ ⋅ N (f2 ) (α , γ , φ 2 ) = 0 (9) The new equations of meshing are in this case: r f(1) (ϕ 0 , θ , φ1 ) = r f( 2) (α , λ , φ 2 ) (1) ∂r f (ϕ 0 , θ , φ1 ) ( 2 ) .n f (α , γ , φ 2 ) = 0 ∂θ (1) (10) θ ∈ D ⊂ E ( 2) (α , γ ) ∈ E (φ , φ ) ∈ E ( 3) 12 ϕ 0 fixed r f(1) (ϕ 0 , θ , φ1 ) = r f( 2 ) (α , λ , φ 2 ) (1) ∂r f (ϕ 0 , θ , φ1 ) ( 2 ) .N f (α , γ , φ 2 ) = 0 ∂θ or θ ∈ D ⊂ E (1) ( 2) (α , γ ) ∈ E (φ , φ ) ∈ E ( 3) 12 ϕ 0 fixed (11) System of equations for meshing is known {(7) or (11)} and the Tooth Contact Analysis is make up to determine φ2, ϕ, θ, α and γ in function of φ1. This mathematical problem has not an explicit solution in general case. We may only have an approximate numerical solution. In this aim, the following method is used: 1. To choose a series of values for φ1. 2. For each value of φ1, to solve the system of equation (7) (6 scalar equations and 6 unknowns). 3. If one of t...
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This note was uploaded on 08/03/2010 for the course DD 1234 taught by Professor Zczxc during the Spring '10 term at Magnolia Bible.

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