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Homework-9 - ´ = 0 ² ′ ³ ´ = 2 ² ³ 3 ´ ³ ´ = −...

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1 AMS 361: Applied Calculus IV by Prof Y. Deng Homework 9 Assignment Date: Wednesday (11/29/2009) Collection Date: Monday (12/07/2009) Please note this special date Grade: Each problem is worth 10 points Problem 9.1: Perform the following inverse transform. (Hint: Please recall my lecture on periodic function) 1 1 ? (1 + ? −𝑎? ) =? Problem 9.2: Use Laplace Transform and another method to solve the following DE and compare the results 𝑥 ′′ 2 𝑥 24 𝑥 = 0 𝑥 0 = 2, 𝑥 0 = 3 Problem 9.3: Use Laplace Transform and another method to solve the following DE and compare the results 𝑥 (4) 5 𝑥 2
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Unformatted text preview: ´ = 0 ² ′ ³ ´ = 2, ² ³ 3 ´ ³ ´ = − 13 µ Problem 9.4 (Pob. 32, P. 481) Solve the following equation ·² ′′ + 2 ³· − 1 ´² ′ − 2 ² = 0 ²³ ´ = 0 µ Problem 9.5 (Pob. 34, P. 481) Solve the following equation ·² ′′ + ³ 4 · − 2 ´² ′ + (13 · − 4) ² = 0 ²³ ´ = 0 µ Problem 9.6 (Pob. 36, P. 481, modified) Find the solution for ² ( · ) by using the convolution theorem to express the solution as the given form. ² ′′ + 4 ² = ?³·´ ²³ ´ = ² ′ ³ ´ = 0 µ ²³·´ = 1 2 ¸ ?¹º 2 » ?³· − »´¼» ·...
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