HW 4 Questions - S = -0.1049 j0.9580, S = -0.2532 j0.3968...

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1 ECE 408 HOMEWORK #4 (CH. 13) 1. The normalized analog pole locations of a filter is given by S = -0.3689 S = -0.1845 ± j0.9231 There are three zeros at S = . These poles and zeros are transformed to bandpass poles and zeros. (a) Find the frequency transformed bandpass poles and zeros when ϖ 1 = 1.0691e+004 rad/s and ϖ 2 = 1.6000e+004. (b) Find the digital poles and zeros when the sampling rate is 8000 Hz. 2. The normalized analog pole locations of a filter are given by S = -0.6829, S = -0.1484 ± j0.5532, S = -0.4758 ± j0.4186 The locations for zeros are S = 0 ± j1.0515, S = 0 ± j1.7013, S = These poles and zeros are transformed to bandstop poles and zeros. (a) Find the frequency transformed bandstop poles and zeros when ϖ 1 = 6.6274e+003 rad/s and ϖ 2 = 2.3946e+004. (b) Find the digital poles and zeros when the sampling rate is 8000 Hz. (c) Find the constant term b 0 such that 1 1 = = z ) z ( H 3. The normalized analog pole locations of a filter are given by
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Unformatted text preview: S = -0.1049 j0.9580, S = -0.2532 j0.3968 The locations for zeros are S = , S = , S = , S = . These poles and zeros are transformed to bandstop poles and zeros. (a) Find the frequency transformed bandstop poles and zeros when 1 = 6.6274e+003 rad/s and 2 = 2.3946e+004. (b) Find the digital poles and zeros when the sampling rate is 8000 Hz. (c) Find the constant term b such that 2 max . z ) z ( H a 05 1 10-= = 4. The specifications of a lowpass IIR filter are: Maximum loss in the passband = 2 dB Minimum loss in the stopband = 55 dB Passband cutoff frequency = 1500 Hz Stopband cutoff frequency = 2000 Hz Sampling rate = 8000 Hz Find the order n and the normalized analog pole and zero locations when the following approximations are used: (a) Butterworth (b) Chebyshev Type I (c) Chebyshev Type II (d) Elliptic...
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This note was uploaded on 08/09/2010 for the course ELECTRICAL ECE 408 taught by Professor Jameskang during the Summer '10 term at Cal Poly Pomona.

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HW 4 Questions - S = -0.1049 j0.9580, S = -0.2532 j0.3968...

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