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Unformatted text preview: 2 signal. 2 J HbHc + H 3 N O O-H a H b H c H b H c H a 2 J HbHc 3 J HaHb 3 J HaHc H d H e H f H d H e 3 J HaHb 3 J HaHc + H 3 N O O-174.24 56.94 37.21 136.30 129.91 130.19 128.42 The multiple signals at 7.2 ppm are the aryl protons. We can see one doublet signal (right side of group) for the two H d protons. The two H e protons (doubllet of doublets) and one H f (doubllet of doublets) are overlapping. By symmetry these two are the same as 129.91 and 130.19 Tryptophan DEPT 13 C NMR Problem N H COO NH 3 DEPT 13 C NMR Problem: Assign signals as C, CH, CH 2 , CH 3 26 ppm CH 2 54 ppm CH 107 ppm C 111 ppm CH 118 ppm CH 119 ppm CH 121 ppm CH 124 ppm CH 126 ppm C 136 ppm C 174 ppm C...
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- Spring '10
- Proton, CH CH CH, 2 j, ppm, SIMI LAR