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Unformatted text preview: 1 + 0 (So q 4 = 0). Thereore gcd(33 , 95) = 1. 5 Solve 33 x + 95 y = gcd(33 , 95) Method 1 We have that: 1 = 297 4 = 297(331 29) = 29 (17(1)) + 33 (7) = (952 33) 8 + 33 (7) = 95 8 + 33 (2 87) = 95 8 + 33 (23) So x = 8 and y =7. 6 Solve 33 x + 95 y = gcd(33 , 95) Method 2 To fnd x , we have that: x 2 =2 x 1 + x =2 (as q 1 = 2) x 3 =1 x 2 + x 1 = 3 (as q 2 = 1) x 4 =7 x 3 + x 2 =23 (as q 3 = 7) To fnd y , we have that: y 2 =2 y 1 + y = 1 y 3 =1 y 2 + y 1 =1 y 4 =7 y 3 + y 2 = 8 So x = 8 and y =7. 7...
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This note was uploaded on 08/12/2010 for the course CRYOPTOGRA 3232 taught by Professor Jhhgjhgjh during the Spring '10 term at Trinity College, Hartford.
 Spring '10
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