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E117CW21 - P 10.33[a First find the'Ihévenin'equivalent...

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Unformatted text preview: P 10.33- [a] First find the 'Ihévenin'equivalent: 40000 j30009 20000 12 0V 120 I: _'______. 6000+j2000 = 18—j6mA 1 . . P = §|I|2(2000) = 360 mW [b] Set CO=O.lp.F so —j/wC= —j20009 j3000—j2000=j10009 Set R, as close as possible to R0 = «#10002 +10002 = 4123.1 Q 120 c I=———=14.7 —- '1. I] 8000+j1000 7 9 85m 1 P = §|I|2(4000) = 443.1 mW Yes; 443.1111W > 360 IIlW 120 d I=——-———=15mA 8000 - 1 P = 5(0.015)2(4000) = 450 mW [e] R0 = 4000 Q; Co = 66.67nF [f] Yes; 450 mW :> 443.1 mW ...
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