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# newnansm9 - Chapter 9: Other Analysis Techniques 9-1 F =...

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Unformatted text preview: Chapter 9: Other Analysis Techniques 9-1 F = \$100 (F/P, 12%, 5) + \$200 (F/P, 12%, 4) - \$100 (F/P, 12%, 1) = \$100 (1.762) + \$200 (1.574) - \$100 (1.120) = 379.00 9-2 F = \$100 (F/P, 10%, 5) + \$100 (F/P, 10%, 3) + \$100 (F/P, 10%, 1) - \$100 (F/P, 10%, 4) - \$100 (F/P, 10%, 2) = \$100(1.611 + 1.331 + 1.100 1.464 1.210) = \$136.80 9-3 P F \$100 \$150 \$200 \$250 \$300 \$100 \$100 \$100 \$100 \$100 F \$100 \$200 \$100 F i = 10% P = \$100 (P/A, 12%, 5) + \$50 (P/G, 12%, 5) = \$100 (3.605) + \$50 (6.397) = \$680.35 F = \$680.35 (F/P, 12%, 5) = \$680.35 (1.762) = \$1,198.78 Alternate Solution F = [\$100 + \$50 (A/G, 12%, 5)] (F/A, 12%, 5) = [\$100 + \$50 (1.775)] (6.353) = 1,199.13 9-4 F = [4x x(A/G, 15%, 4)] (F/A, 15%, 4) = [4x x(1.326)] (4.993) = 13.35x Alternate Solution F = 4x (F/P, 15%, 3) + 3x (F/P, 15%, 2) + 2x (F/P, 15%, 1) + x = 4x (1.521) + 3x (1.323) + 2x (1.150) + x = 13.35x 4x 3x 2x x F i = 15% 9-5 F = \$5 (P/G, 10%, 6) (F/P, 10%, 12) + \$30 (F/A, 10%, 6) = \$5 (6.684) (3.138) + \$30 (7.716) = 383.42 9-6 P system 1 = A (P/A, 12%, 10) = \$15,000 (5.650) = \$84,750 P system 2 = G (P/G, 12%, 10) = \$1,200 (20.254) = \$24,305 P Total = \$84,750 + \$24,305 = \$109,055 F Total = P Total (F/P, 12%, 10)= \$109,055 (3.106) = \$338,725 9-7 i a = (1 + r/m) m 1 = (1 + 0.10/48) 48 1 = 0.17320 F = P (1 + i a ) 5 = \$50,000 (1 + 0.17320) 5 = \$111,130 9-8 P \$5 \$10 \$15 \$20 \$25 A = \$30 F i = 12% P 20 P 65 \$100 G = \$100 .. 21 55 P 20 = \$100 (P/A, 12%, 35) + \$100 (P/G, 12%, 35) = \$100 (8.176) + \$100 (62.605) = \$7,078.10 P 65 = P 20 (F/P, 12%, 45) = \$7,078.10 (163.988) = \$1,160,700 9-9 F = \$30,000 (F/P, 10%, 15) + \$600 (F/A, 10%, 15) = \$30,000 (4.177) + \$600 (31.772) = \$144,373 9-10 F = \$3,200 (F/A, 7%, 30) + \$60 (P/G, 7%, 30) (F/P, 7%, 30) = \$3,200 (94.461) + \$60 (120.972) (7.612) = \$357,526 9-11 F = \$100 (F/A, %, 24) (F/P, %, 60) = \$100 (25.432) (1.349) = \$3,430.78 \$30,000 A = \$600 n = 15 F \$3,200 G = \$60 ... F n = 30 9-12 P = \$100 (P/A, 18%, 10) + \$50 (P/G, 18%, 10) = \$100 (4.494) + \$50 (14.352) = 1,167.00 F = \$1,167 (F/P, 18%, 10) = \$1,167 (5.234) = 6,108.08 9-13 F = 100 (1 + 0.10) 800 = 1.3 x 10 35 9-14 F = \$150 (F/A, %, 4) (F/P, %, 14) + \$100 (F/A, %, 14) = \$150 (4.030) (1.072) + \$100 (14.464) = 2,094.42 \$100 g = +\$50 \$550 F P i = 18% \$150 \$100 F i = % 9-15 Using single payment compound amount factors F = \$1,000 [(F/P, 4%, 12) + (F/P, 4%, 10) + (F/P, 4%, 8) + (F/P, 4%, 6) + (F/P, 4%, 4) + (F/P, 4%, 2)] = \$1,000 [1.601 + 1.480 + 1.369 + 1.265 + 1.170 + 1.082] = \$7,967 Alternate Solution A = \$1,000 (A/P, 4%, 2) = \$1,000 (0.5302) = \$530.20 F = \$530.20 (F/A, 4%, 12) = \$530.20 (15.026) = \$7,966.80 9-16 x = years to continue working age to retire = 55 + x \$1,000 F \$1,000 A A ....
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## This note was uploaded on 08/13/2010 for the course IME IME 314 taught by Professor Freeman during the Spring '10 term at Cal Poly.

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newnansm9 - Chapter 9: Other Analysis Techniques 9-1 F =...

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