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Unformatted text preview: Chapter 9: Other Analysis Techniques 91 F = $100 (F/P, 12%, 5) + $200 (F/P, 12%, 4)  $100 (F/P, 12%, 1) = $100 (1.762) + $200 (1.574)  $100 (1.120) = 379.00 92 F = $100 (F/P, 10%, 5) + $100 (F/P, 10%, 3) + $100 (F/P, 10%, 1)  $100 (F/P, 10%, 4)  $100 (F/P, 10%, 2) = $100(1.611 + 1.331 + 1.100 1.464 1.210) = $136.80 93 P F $100 $150 $200 $250 $300 $100 $100 $100 $100 $100 F $100 $200 $100 F i = 10% P = $100 (P/A, 12%, 5) + $50 (P/G, 12%, 5) = $100 (3.605) + $50 (6.397) = $680.35 F = $680.35 (F/P, 12%, 5) = $680.35 (1.762) = $1,198.78 Alternate Solution F = [$100 + $50 (A/G, 12%, 5)] (F/A, 12%, 5) = [$100 + $50 (1.775)] (6.353) = 1,199.13 94 F = [4x x(A/G, 15%, 4)] (F/A, 15%, 4) = [4x x(1.326)] (4.993) = 13.35x Alternate Solution F = 4x (F/P, 15%, 3) + 3x (F/P, 15%, 2) + 2x (F/P, 15%, 1) + x = 4x (1.521) + 3x (1.323) + 2x (1.150) + x = 13.35x 4x 3x 2x x F i = 15% 95 F = $5 (P/G, 10%, 6) (F/P, 10%, 12) + $30 (F/A, 10%, 6) = $5 (6.684) (3.138) + $30 (7.716) = 383.42 96 P system 1 = A (P/A, 12%, 10) = $15,000 (5.650) = $84,750 P system 2 = G (P/G, 12%, 10) = $1,200 (20.254) = $24,305 P Total = $84,750 + $24,305 = $109,055 F Total = P Total (F/P, 12%, 10)= $109,055 (3.106) = $338,725 97 i a = (1 + r/m) m 1 = (1 + 0.10/48) 48 1 = 0.17320 F = P (1 + i a ) 5 = $50,000 (1 + 0.17320) 5 = $111,130 98 P $5 $10 $15 $20 $25 A = $30 F i = 12% P 20 P 65 $100 G = $100 .. 21 55 P 20 = $100 (P/A, 12%, 35) + $100 (P/G, 12%, 35) = $100 (8.176) + $100 (62.605) = $7,078.10 P 65 = P 20 (F/P, 12%, 45) = $7,078.10 (163.988) = $1,160,700 99 F = $30,000 (F/P, 10%, 15) + $600 (F/A, 10%, 15) = $30,000 (4.177) + $600 (31.772) = $144,373 910 F = $3,200 (F/A, 7%, 30) + $60 (P/G, 7%, 30) (F/P, 7%, 30) = $3,200 (94.461) + $60 (120.972) (7.612) = $357,526 911 F = $100 (F/A, %, 24) (F/P, %, 60) = $100 (25.432) (1.349) = $3,430.78 $30,000 A = $600 n = 15 F $3,200 G = $60 ... F n = 30 912 P = $100 (P/A, 18%, 10) + $50 (P/G, 18%, 10) = $100 (4.494) + $50 (14.352) = 1,167.00 F = $1,167 (F/P, 18%, 10) = $1,167 (5.234) = 6,108.08 913 F = 100 (1 + 0.10) 800 = 1.3 x 10 35 914 F = $150 (F/A, %, 4) (F/P, %, 14) + $100 (F/A, %, 14) = $150 (4.030) (1.072) + $100 (14.464) = 2,094.42 $100 g = +$50 $550 F P i = 18% $150 $100 F i = % 915 Using single payment compound amount factors F = $1,000 [(F/P, 4%, 12) + (F/P, 4%, 10) + (F/P, 4%, 8) + (F/P, 4%, 6) + (F/P, 4%, 4) + (F/P, 4%, 2)] = $1,000 [1.601 + 1.480 + 1.369 + 1.265 + 1.170 + 1.082] = $7,967 Alternate Solution A = $1,000 (A/P, 4%, 2) = $1,000 (0.5302) = $530.20 F = $530.20 (F/A, 4%, 12) = $530.20 (15.026) = $7,966.80 916 x = years to continue working age to retire = 55 + x $1,000 F $1,000 A A ....
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This note was uploaded on 08/13/2010 for the course IME IME 314 taught by Professor Freeman during the Spring '10 term at Cal Poly.
 Spring '10
 Freeman

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