This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: FIT1001: RevisionLN05_ans Page 1 of 3 &amp; &amp; &amp; &amp; &amp; 1. A non-pipelined system takes 300ns to process a task. The same task can be processed in a 5-segment pipeline where each segment takes 60ns. Determine the speedup ratio of the pipeline for 100 tasks. What is the maximum speedup that could be achieved with the pipeline unit over the non- pipelined unit? SOLUTION: 8 . 4 6240 30000 60 ) 1 100 ( 60 5 100 300 = = - + = ns ns ns SpeedUp Maximum speed-up =5 (number of segments in the pipeline)....
View Full Document
- Three '10