New SAT Math Workbook

1 01 11 wwwpetersonscom 152 chapter 10 solutions to

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Unformatted text preview: ctly (A) 14.2 (B) 14.3 (C) 14.8 (D) 14.9 (E) 14.6 The number of digits in the square root of 14,161 is (A) 5 (B) 4 (C) 3 (D) 2 (E) 6 (2 3 )5 is equal to 3. The product of a 2 x and x 6 x is (A) (B) (C) (D) (E) 2ax 2 3 8. 12ax3 (2ax )2 3 12ax2 12ax 9. 4. Divide 42 40r 3t 6 by 3 5rt 2 (A) (B) (C) (D) (E) 56rt 2 2 28rt 2rt 28rt 2 2 28rt 2t 5. 56rt 2t 3 Solve for x: = .09 x (A) (B) (C) (D) (E) 10. Find (A) (B) (C) (D) (E) 32 3 288 3 10 3 90 3 16 3 25m 4 36c64 d 16 5m 2 6c8 d 4 5m 2 6c32 d 4 5m 2 6c32 d 8 5m 2 6c8 d 8 5m 6c16 d 4 (A) (B) (C) (D) (E) 10 1 .1 .01 1.1 www.petersons.com 152 Chapter 10 SOLUTIONS TO PRACTICE EXERCISES Diagnostic Test 1. (B) 75 = 25 ⋅ 3 = 5 3 Exercise 1 1. (E) 4 27 = 4 9 ⋅ 3 = 12 3 12 = 4 ⋅ 3 = 2 3 5 3+2 3=7 3 2 48 = 2 16 ⋅ 3 = 8 3 147 = 49 ⋅ 3 = 7 3 12 3 − 8 3 + 7 3 = 11 3 2. (B) 125 = 25 ⋅ 5 = 5 5 45 = 9 ⋅ 5 = 3 5 5 5−3 5 = 2 5 2. (B) 80 = 16 ⋅ 5 = 4 5 3. 4. (D) (B) 2 = .4 x 2 = .4 x x=5 9 x ⋅ 4 x = 36 x 2 = 6 x 45 = 9 ⋅ 5 = 3 5 20 = 4 ⋅ 5 = 2 5 4 5+3 5−2 5 =5 5 .16 = .4 Multiply by x. 3. (C) Only terms with the same radical may be combined. 6 5−4 5 =2 5 3 2+ 2 =4 2 5. 6. (C) Since the last digit is 6, the square root must end in 4 or 6. (B) Since the number has two digits to the right of the decimal point, its square root will have one digit to the right of the decimal point. (E) 25 x 2 + 36 x 2 61x 2 61 = =x 900 900 30 Therefore we have 2 5 + 4 2 4. (B) 1 1 ⋅ 180 = ⋅ 36 ⋅ 5 = 3 5 2 2 7. 8. (E) It is not possible to find the square root of separate terms. (C) 8 12 23 = 4 4 = 4⋅2 = 8 9. 1 1 ⋅ 45 = ⋅ 9 ⋅ 5 = 3 3 2 2 ⋅ 20 = ⋅ 4 ⋅ 5 = 5 5 4 3 5+ 5− ⋅ 5=4 5 1 16 =3 5= 5 5 5 5 4 5 5 4 5 5− 5 10. (D) ( 2 )( 2 ) = 2 . Therefore, 5. (A) 5 mn − 5 mn = 0 ( 2) ⋅( 2) ⋅ 2 ⋅ 2 ⋅ 2 = 4 2 www.petersons.com Roots and Radicals 153 Exercise 2 1. 2. 3. (A) (B) (A) 2 18 ⋅ 6 2 = 12 36 = 12 ⋅ 6 = 72 Exercise 3 1. 2. (B) 16 x 2 + 9 x 2 = 144 25 x 2 5 x = 144 12 3 3 ⋅ 3 3 ⋅ 3 3 = 27(3 3 ) = 81 ⋅ 3 Using the distributive law, we have 3. 4....
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This note was uploaded on 08/15/2010 for the course MATH a4d4 taught by Professor Colon during the Spring '10 term at Embry-Riddle FL/AZ.

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