New SAT Math Workbook

B these numbers are evenly spaced so the average is

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Unformatted text preview: 3, 23, 33, 43. Since these are evenly spaced, the average is the middle integer, 23. (A) 160 + 185 + 210 + 200 + 195 = 950 950 = 190 5 3. 4. (A) 93 is 1 above 92; 88 is 4 below 92. So far, she has 1 point above 92 and 4 points below 92. Therefore, she needs another 3 points above 92, making a required grade of 95. (E) W+x =A 2 4. 5. (B) These numbers are evenly spaced, so the average is the middle number, 3a. (B) 111 6 4 3 13 ++= + + = 2 3 4 12 12 12 12 1 3 5. To divide this sum by 3, multiply by 13 1 13 ⋅= 12 3 36 W + x = 2A x = 2A – W 6. (C) 4 lb. 10 oz. 6 lb. 13 oz. + 3 lb. 6 oz. 13 lb. 29 oz. 13lb. 29oz. 12lb. 45oz. = = 4 lb. 15 oz. 3 3 7. (B) 4 ( 50 ) = 200 2 ( 60 ) = 120 6)320 53 1 3 8. (C) 3(140 ) = 420 8)1920 240 5 ( 300 ) = 1500 9. (E) The average of any three numbers that are evenly spaced is the middle number. 10. (D) Since 88 is 2 below 90, Mark is 8 points below 90 after the first four tests. Thus, he needs a 98 to make the required average of 90. www.petersons.com 112 Chapter 7 Exercise 2 1. (D) 88 is 4 below 92; 94 is 2 above 92; 91 is 1 below 92. So far, he has 5 points below 92 and only 2 above. Therefore, he needs another 3 points above 92, making the required grade 95. (B) X +Y + x =M 3 Exercise 3 1. (A) 8 (125) = 1000 24)2880 120 3( 60 ) = 180 6 (120 ) = 720 10 (116 ) = 1160 2. 2. (C) X + Y + x = 3M x = 3M – X – Y 3. (C) 4 ( 55) = 220 7)400 1 57 , 7 ( x + 3) + n = 2 x 2 x + 3 + n = 4x n = 3x – 3 which is 57.1 to the nearest tenth. 3. (B) 5 (15, 000 ) = 75, 000 1 (18, 000 ) = 18, 000 3(17, 000 ) = 51, 000 4. (D) 86° is 2 above the average of 84; 82° is 2 below; 90° is 6 above; 92° is 8 above; 80° is 4 below; and 81° is 3 below. So far, there are 16° above and 9° below. Therefore, the missing term is 7° below the average, or 77°. (C) 17 must be the middle integer, since the five integers are consecutive and the average is, therefore, the middle number. The numbers are 15, 16, 17, 18, and 19. 9)144, 000 16, 000 4. (A) 5. 6 (100 ) = 600 4 ( 5...
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This note was uploaded on 08/15/2010 for the course MATH a4d4 taught by Professor Colon during the Spring '10 term at Embry-Riddle FL/AZ.

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