New SAT Math Workbook

# In 2 equation e is the slope and 3 is the y3 intercept

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: fastest combined time. As you can see, OA is the shortest segment, showing that cyclist A finished the two races in the fastest combined time. (Although six points are located above the ray, while only four are located below the ray, the ones below the ray, as a group, are further from the ray; so the overall distribution of values is fairly balanced above versus below the ray.) Any ray with a significantly flatter slope (answer choice A or B) or steeper slope (answer choice D or E) would not extend through the “middle” of the ten points and therefore would not indicate an accurate average (race 1):(race 2) ratio. 5. (C) You can approximate the (race 1):(race 2) time ratio for the ten cyclists as a group by drawing a ray extending from point O through the “middle” of the cluster of points—as nearly as possible. Each of the five answer choices suggests a distinct slope for the ray. Choice (C) suggests a ray with slope 1 (a 45° angle), which does in fact appear to extend through the middle of the points: 2. 3. www.petersons.com Additional Geometry Topics, Data Analysis, and Probability 309 Exercise 6 1. (D) There are two ways among five possible occurrences that a cherry candy will be selected. Thus, the probability of selecting a 2 cherry candy is 5 . (B) In each set are three distinct member pairs. Thus the probability of selecting any pair 1 is one in three, or 3 . Accordingly, the probability of selecting fruit and salad from the appetizer menu along with squash and peas 111 from the vegetable menu is × = . 33 9 Retest 1. (E) Since the figure shows a 45°-45°-90° triangle in which the length of the hypotenuse is known, you can easily apply either the sine or cosine function to determine the length of either leg. Applying the function cos45° = set the value of this function equal to 2 x 2 2 adjacent hypotenuse , then solve for x: x = ; 2x = 4 2 2 ; 2x = 8 ; x = 4 . 42 2 , 2 2. 3. (E) You must first calculate the chances of picking the same student twice, by multiplying together the two individual probabilities fo...
View Full Document

## This note was uploaded on 08/15/2010 for the course MATH a4d4 taught by Professor Colon during the Spring '10 term at Embry-Riddle FL/AZ.

Ask a homework question - tutors are online