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# DOC017 - Name{Elag‘rerg QUE—EB “57 99 Not neat Not...

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Unformatted text preview: Name {Elag‘rerg QUE—EB “57/ 99 Not neat? Not legible? Cannot follow your work at a glance? -50 points! P] Problem 1) The W 12x50 cantilever beam shown is subjected to a load on the end of the beam (P1 = 20 kips) in the negative Y direction. The load in the negative X direction (P2) is unknown, A load in the negative Z direction (P3 = 2 kips) is also applied. If the allowable stress in the steel is 50 ksi, determine the maximum load P2 that can be placed on the beam. The beam is 5 feet long. P2 You may omit shear stress calculations, since they are small. +———————L———> P3 Problem 2) Draw a shear and moment diagram for the beam loaded as shown. M = 200 k ft, wl = 3 k/ft, w2 = 4k/ﬁ,L1=6ﬁ,L2=16ﬁ,L3 =8ﬁ,L4=6ﬁ. Problem 3) Using Mohr's circle, determine the maximum stresses in a block for which sigma x = 20 ksi tension, sigma y = 12 ksi tension, and the shearing stress is 8 ksi acting up on the right vertical face of the block. lcllblO C Problem 4) Determine the maximum shearing stress induced in a beam which is ' subjected to a maximum shear load of 200 kips. The ﬁgure shows an end View of the beam. Use a = 3 inches, b = 2 inches, 0 = 4 inches and d = 6 inches. Problem 5) An engineer at NASA recognized that the bending stresses on the free end of the cantilever beam shown below would be small, since the moments at the free end are small. He therefore proposed that a lighter beam could be constructed which would be stressed equally from the free end to the wall, by varying the height of the beam. Determine the required height of the beam at the 2", 4", 6" and 8" positions, if the allowed bending stress in the beam is 30 ksi, and the thickness t of the beam is to be 1 inch. The beam is 8 inches long, and is loaded with P = 62.5 kips on the free end. You may omit shearing stresses for this problem. \\\\\\\\\\\\\\\ 1 2" 2" 2" 2" 3?? ﬁM’D wm x. m‘mnw vague; Egg)? WM?“ aifﬁcadﬁ { \NQ CQAW )Lﬂe’kawg "3“‘33 mag-3; gay“) j" 3 A)[email protected]§€ @ MW W f '75 f E .. 2L3. ANN: manila ELI). ...\1:M D‘Aem-MAm3 -. 4W bow % 3 '5/ t if “ , mm A! 2M arm-LAMA ' '” ‘“' “ “W300 WWW, /‘ ..-.. _-(4Xh)@8)Kﬁb-. + R (3.10% 2M —:0 ' —2\ook9£ + 3(lelt03kS‘k _ EEG?» .3; m» x l .. # ...:...-.---...---_ "A ._.~LA .. ..A 345313., ﬁ)fljo;La}l:JJ-i9_ £31.- . -.-..- -.--A_-.---..-.--._.«-_..----..---_--_... .. . A3.- 1313.53.51 ..... £19403. £t3'- . -. ,. ._--_._- . -.- A4 179900)- .1 .__-m__. Wﬁpﬂ i z i 2 L 1 i s b LL . ._ A A .. - __._ ..... .A [(10 9.1%; ELbMLW Y: 8130. 11:99. -A- “A, M - m MW i ELND MK (2me 536%. (cm) ______ - TM A 23A A'O‘NXWW WW) ‘= AAA; :1: @KM’W) 71g “274 I, [%"‘/89 73\$; w 0% % 6) gwmt «we omnsquwb smessas 0”02:93mm mum {find .20: 3ka ...
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