Lesson_26 - Lesson 26 Lesson 26 Challenge 25 Lesson 26 Continuous-time signals and systems Challenge 26 Lesson 26 Challenge 25 A continuous time

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Unformatted text preview: Lesson 26 Lesson 26 Challenge 25 Lesson 26 - Continuous-time signals and systems Challenge 26 Lesson 26 Challenge 25 A continuous time system is defined by an integrator which has an initial condition y(0). If presented with a continuous-time input x(t), the output is: Is the system linear? ( 29 ( 29 ( 29 y d x t y t + = ∫ τ τ Lesson 26 Challenge 25 Let x 1 (t) be given, Let x 2 (t) be given, Let x(t)= x 1 (t)+ x 2 (t), But y 1 (t)+ y 2 (t), System is non-linear. ( 29 ( 29 ( 29 1 1 y d x t y t + = ∫ τ τ ( 29 ( 29 ( 29 2 2 y d x t y t + = ∫ τ τ ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 2 1 2 1 y d x d x y d x x t w t t t + + = + + = ∫ ∫ ∫ τ τ τ τ τ τ τ ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 . 2 2 1 t w y d x d x t y t t ≠ + + = ∫ ∫ τ τ τ τ Lesson 26 Lesson 26 Linear convolution: What are the evaluation methodologies? Integrate (use a computer) Transforms (to be introduced) Graphical ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 τ τ τ τ τ τ d h t x d t h x t x t h t y ∫ ∫ ∞ ∞- ∞ ∞-- =- = =...
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This note was uploaded on 08/21/2010 for the course EEL 3135 taught by Professor ? during the Spring '08 term at University of Florida.

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Lesson_26 - Lesson 26 Lesson 26 Challenge 25 Lesson 26 Continuous-time signals and systems Challenge 26 Lesson 26 Challenge 25 A continuous time

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