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# class40 - Todays class: More on superposition states and...

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Today’s class: • More on superposition states and ‘Measurements’ Announcements This Friday: • Online survey due (extra credit) • Last graded HW due • Exam3 will be returned. If you have concerns/corrections about Exam3 grading: Talk to me today! (1-3pm) Superposition state 2 2 2 1 1 2 1 2 ) , ( ) , ( ) , ( t x t x t x Ψ + Ψ = Ψ Ψ 2 (x,t) Ψ 1 (x,t) n (x,t)| 2 = | ψ n (x)| 2 : time in dependent But: ) / ) cos(( ) ( ) ( ) ( ) ( 1 2 2 1 2 2 2 1 2 1 2 1 h t E E x x x x + + = ψ x In simple terms: What does it mean for a particle to be in a superposition of states Ψ 1 (x,t) and Ψ 2 (x,t) ? A. There are two particles, one described by Ψ 1 (x,t) and the other described by Ψ 2 (x,t) , that travel together in a packet. B. The probability density of finding the particle at position x at time t is given by the absolute square of the sum of the two wave functions, each multiplied by some factor. Q1 C. The particle is located at a position somewhere in between the position described by Ψ 1 (x,t) and the position described by Ψ 2 (x,t) . D. The particle has an energy somewhere in between the energies E 1 and E 2 . E. More than one of the answers above is true. Probability density

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## This note was uploaded on 08/24/2010 for the course PHYS 2130 taught by Professor Staff during the Spring '08 term at Colorado.

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class40 - Todays class: More on superposition states and...

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