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7a) Test and CI for One Proportion: C1 Event = Y Variable X N Sample p 95% CI C1 14 40 0.350000 10.206282, 0.516844) Test and CI for One Proportion: C1 Test of p = 0.5 VS P < 0.5 = Y 95% Upper Exact X N Sample P Bound P-Value C1 14 40 0.350000 0.491946 0.040 Since our p-value is less than our alpha of 0.05 we reject the null hypothesis and can conclude that there is enough evidence to conclude that the proportion of all employees with experience or knowledge of ADHD is less than 0.5 Test of p = 0.5 vs p < 0.5 = Y X N 2-Value 14 40 0.350000 0.474047 -1.90 0.029 Using the normal approximation. 8a
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- Histogram of TAXESSnassau 6 5 4 1 2 1 0 TAXB_nassau TAXES-suffolk 9 8 7 6 ii f4 3 2 1 0 3500 4000 4500 5500 TAX=-su(lok -
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Descriptive Statistics: TAXES-nassau, TAXES-suffolk Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 TnxES-nassau 25 0 2822 118 588 2027 2340 2741 3149 TAXES-suffolk 0 3815 149 744 2800 3235 3640 4310 r,
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This note was uploaded on 08/25/2010 for the course AEM 2100 taught by Professor Vanes,c. during the Spring '08 term at Cornell University (Engineering School).

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HW%2011%20Answer%20Key - / c-

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