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# Homework_9_Answer_Key - ,La 1 4'UU S pring 2009 H omework 9...

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, , , L a 1 4'UU Spring 2009 Homework 9 Answer liey 1a0l0, ao. 30%) qr./, CI . \ t33 de are 95% mnSident +hat :She above in+erml contains +he population mean tip percentage. a)n) Minimum ~ondi+ions: np" - (1500)10.53)= 795 2 5 nLl-p') = (1500)(~.~7) = 7 0 5 5

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bl Hinimum conditions: np^ = 11500)(0.31)= Y65.s 5 nL\-F)= nsoo)lo.69) = 1035 2 5 C) M i n i m condi+ions: np" = 11500)L0.05) = 75% 5 rill-p)= (1500)L0.95) = Ill252 5
c31 aa)d f i e mrgin of errm is greates+ b r [a\ and least for (c), u ~ i t h (bl kalling in behueen. Part La) has +he larges4 margin of error because t h e value OF is closes4 0.5. la 3) = 93/100= 0.83 . Minimum conditions : np^ = 1100)10.83) = 83 5 5 nLI-$) = llOO)(O.17) = 17 5- 5 Ell, "/id = loo/9a~3 = 0.01 a L 0.05 -, ignore FPC [il =?JF = 0.0376 This preview has intentionally blurred sections. Sign up to view the full version. View Full Document C37 c) The conSidence interval computed in [a) is more narrow than the conhdence interval cornpu-led in (b). A population size Peguiring use o t h e Finite PopuIahon Correch-cm$actor yields a smaller sampling erco r.
C1'1 Lob) CI di&h = a0 = am.0353) = 0.0706 No, do~b\in\;ng n only reduces +he wid4-h to 0.0706. C3I bl We are 80% con\$idenS +ha+ +he above inkr~a\ ~ n t a i n s the population propor-kion 0% eonsumen

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Homework_9_Answer_Key - ,La 1 4'UU S pring 2009 H omework 9...

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