# Homework_8_Answer_Key - AEM 2\00 Spring 2009 H omel~ork...

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AEM 2\00 Spring 2009 Homel~ork 8 Ansaer key @I IId Norma\ Pqcoxima+ion , Minimum conditions: np- (900N0.53) = aia 2 5 n[bp1 = (900110.47) = 188 2 5 50% 05 the sample actually obfained relie*, it would sugqest +ha+ She mrnufacfurerk claim is corred since there a reasonable chance [11.5%) of Shis hsppening iS p= 0.53. b) Apocoximation conditions : np = 110001 (0.53) = 530 2 5 n (I-p) - (1000)(0.97) = q70 r 5

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~.- (31 l)b) 2" = \$- p = 0.5-0.53 =.-I.q.j look up + 0.Y713 0") r\$ 50'10 05 She sample obfained relie4 in this use, we doul d be (31 much more confident that the rnanuf.achcrerb claim is tncorrec-f US -there is nou only 2.9% chance of happening iG p-0.53 [compared b 11.5% in part [a\\. Q2) flormal Apqroxirnaiion Minimum conditions: np- 135)[0.5)= 17.5? 5 n (1- p) = 1351 LO. 5) - 17.5 2 5
L37 C) The probabilities obtained in pmts la) and ib) are valid when: npb 5 nil-pl' 5 C31 dl The homial Distribution should be used Sor a small sample Size when he Normal DistcihuJrion canno+ used. m3) Nnrmal Appcexijna+im Hinimum conditions : np = 1380110.'l\ = 152 l5 dl-PI = (380N0.6) = aas ? 5

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- . Hac9in a\$ Error = zmIa LdG I C13. = 1.96 (~1000/~) Gal = 1.96(516.398) = lola. 14 For a Hargin o\$ Error 05 8500: 1: 13 1.46/4000/G) = SO0 LII YOOO = a55.1oa - G CU = 15.68 n = a~s.86
dL33 S)a\ None. because n is grea-ter than 30. [33 We are %'lo cdident that our interval eonfains the popuIa+ion Mean loss in home valltes. LqI d Yes.

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## This note was uploaded on 08/25/2010 for the course AEM 2100 taught by Professor Vanes,c. during the Spring '08 term at Cornell.

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Homework_8_Answer_Key - AEM 2\00 Spring 2009 H omel~ork...

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