# Homework_2_Answer_Key-2009 - AEM 2\00 S pring 2 009 H...

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' AEM 2\00 Spring 2009 , Horneoock a Answer Key EI 1) Ocder Data: C17 Md: i= tp1100)n = (5011001 10 = 5 + a~g. 5"' and Grn values cal Md= 73+ 8% = \78.5 visi+orsl C31 The mean is qreater than the median, indica+ing that data skewed b cight. CAI ji= z~i = a 331 1 1 + 18ia)+9[3)+ alrl + 10715) n 365 365 The median remains he same &ile +he mean increases by 1-39 partners .

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a31 Order ~ah: -a7 4 1 \I \Y - 4 7 I\ 1'4- 35 SS ~t0ta\ -7 Lt 7 \I \? -5 l.r- \\ A, o 6 8 la a+ 0 b S \+ 39 4 6 10 I+ [1'1 C) 4% (Q,) and fiyo (Q3) [I1 lowest change = mina 3% ~O~~~LXKJ highest = maw = SOP Lrnn+n and knawler - E(d: L- 10.5) 35 - 17.5 18" value =& C11 g5* percentile =A.%o C33 3: *ink AS~ica has the larger standard deuia+ia because -!-he spread 0% +he da+a is gceaSer.
qlb) Western Europe: [a3 sa= c~~-[cc~I)~- - sasra- 13qaroo = 15.33 = l.Oqsyma n A IS n- \ 1% L~I s = "ls"= 4 50.ql7 = 7.136 years =\2Ld cll\YeJ this con%irrns my response in part (a). AS~ica, mi* +he larger range, has the larger ~+andard devia+ion. (31 C) 3: wu\d expect he s+andard devidion Co be t arge r because value \$0~ Russia is muoh smdec +ban rest; adding additional spcead to data. Wi+h Russia, range increases 15 years and standard devia+im to 3.6

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## This note was uploaded on 08/25/2010 for the course AEM 2100 taught by Professor Vanes,c. during the Spring '08 term at Cornell.

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Homework_2_Answer_Key-2009 - AEM 2\00 S pring 2 009 H...

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