fin06sol - I S M T 1 1 1 F 0 6 F i n a l E x a m Suggested...

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ISMT111 F06 Final Exam Suggested Solution Question 1: (a) 71.5 26 / 55 . 30 06 . 2 × ± =71.5 ± 12.34 = [59.16, 83.84] (b) With 95% confidence the true mean will be enclosed in the interval. That is, if we take a large number of samples and construct the intervals as in (a) then 95% of the intervals will enclose the true mean. (c) (80.55+59.45)/2=70 (d) (80.55-59.45)/2=10.45. SE=10.55/1.96=5.33 (e) 4 . 61 8 ) 98 . 31 ( ) 96 . 1 ( 2 2 2 = n , 62 = n (f) 0.111 36 / ) 9 8 ( 9 1 96 . 1 × ± =0.111 ± 0.103 Question 2: (a) 0 : vs 0 : 1 2 1 2 0 > = p p H p p H a ( b) 645 . 1 087 . 1 0552 . 0 06 . 0 180 1 150 1 ) 330 156 1 ( 180 150 90 66 ) 44 . 0 5 . 0 ( < = = + + + , accept 0 H . that the economic outlook this year is not better than last year. (c) p-value = 0.1379 (d) 0526 . 0 } 62 . 1 { } 180 / ) 56 . 0 ( 44 . 0 44 . 0 5 . 0 { } 5 . 0 ˆ { 2 = > = > = > Z P Z P p P . Question 3: (a) Sample means have normal distribution with mean 3 and variance
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This note was uploaded on 08/26/2010 for the course ISOM ISOM111 taught by Professor Anthonychan during the Spring '09 term at HKUST.

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