Prbset06

# Prbset06 - CHEMICAL ENGINEERING THERMODYNAMICS COURSE NO.:...

This preview shows pages 1–2. Sign up to view the full content.

CHEMICAL ENGINEERING THERMODYNAMICS COURSE NO.: CHEG301 STUDENT: ___________________ COURSE: Thermodynamics INSTRUCTOR: Prof. Anderson SUBJECT: Problem Set 06 DUE: Wednesday, Oct. 3, 2007 1. Estimate the value of C v , for propylene at 100 ° C, 0.0928 gr/cm 3 (41 atm) using only the data given below. Compare your result with the experimental value of 0.434 cal/gr-K. Ideal gas heat capacity at constant pressure: T, K C , cal/gmol-K p * 300 15.34 400 19.10 500 22.62 The P-V-T data below express the gas density in terms of Amagat units. This unit is dimensionless and simply expresses the ratio of the true density to the density at 1 atm and 273K, which for propylene is 4.544 × 10 -5 gmol/cm 3 . Density Pressure, atm Amagats 75 ° C 100 ° C 125 ° C 6.4976 7.8365 8.4920 9.1415 8.3409 9.8430 10.7020 11.5514 10.1832 11.7558 12.8257 13.8818 12.1074 13.6579 14.9562 16.2349 14.3997 15.7973 17.3793 18.9330 16.6494 17.7674 19.6391 21.4729 18.3557 19.1775 21.2770 23.3297 19.5100 20.0937 22.3483 24.5522 23.0078 22.6744 25.4271 28.1038 27.6638 25.6809 29.1347 32.4745 32.1907 28.1611 32.3417 36.3613 36.9366 30.3249 35.3143 40.0840 41.6597 32.0613 37.9045 43.4519 42.4108 - 38.2855 43.9626 46.1992 - 40.0797 46.4052 47.3154 - 40.5730 47.0935 50.9531 - 42.0618 49.2283 Hint: Because the pressure data are given at equally spaced temperatures, you can use finite differences to estimate the second derivative of pressure with respect to temperature.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 08/26/2010 for the course CHEG 301 taught by Professor Anderson during the Fall '07 term at UConn.

### Page1 / 3

Prbset06 - CHEMICAL ENGINEERING THERMODYNAMICS COURSE NO.:...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online