{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

3661199136

# 3661199136 - t T ∂ ∂ = ∂ ∂ 0.0 0.40 0.64 0.64 0.40...

This preview shows pages 1–2. Sign up to view the full content.

Tutorial questions: Chapter 5 EX1. Determine the types of the following PDEs (a) (b) Ans. (a) Parabolic PDE. (b) Elliptic PDE EX2. Calculate the partial differentiation of the following function x T k t T 2 2 = 0 2 2 2 2 = + y T x T 2 2 2 ) , , ( z y x z y x u + + = Ans. 6 2 = u z u y u x u u 2 2 2 2 2 2 2 + + = EX3. Verify by direct substitution that is a solution to the heat transfer equation for any integer n=1, 2, 3, … t kn e x n t x T 2 2 ) sin( ) , ( π = 2 2 x T k t T =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
EX4. . Verify by calculating using the forward different method and using the central different method that the temperatures listed in the table below are solutions to the heat transfer equation at time t=0.02 t T / 2 2 / x T 2 2 x T
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: t T ∂ ∂ = ∂ ∂ 0.0 0.40 0.64 0.64 0.40 0.0 t=0.04 0.0 0.48 0.80 0.80 0.48 0.0 t=0.02 0.0 0.64 0.96 0.96 0.64 0.0 t=0 x 6 =1.0 x 5 =0.8 x 4 =0.6 x 3 =0.4 x 2 =0.2 x 1 =0 EX5. Establish a PDE, initial condition and boundary condition for the following heat transfer problem: A long thin rod with a length of 10cm is made from aluminium (Al). The thermal conductivity of Al is k=0.49 (cal/s ⋅ cm ⋅° C); The heat capacity of Al is C v =0.2174 (cal/g ⋅° C). The density is ρ =2.7 (g/cm 3 ). T(x=0)=100 ° C; T(x=10cm)=50 ° C At t=0, T=0 ° C...
View Full Document

{[ snackBarMessage ]}

### Page1 / 2

3661199136 - t T ∂ ∂ = ∂ ∂ 0.0 0.40 0.64 0.64 0.40...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online