exam3 kns - Version 032 Exam 3 gualdani (56455) This...

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Version 032 – Exam 3 – gualdani – (56455) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points IF the graph oF f is which one oF the Following contains only graphs oF anti-derivatives oF f ? 1. 2. 3. 4. correct 5. 6. Explanation: IF F 1 and F 2 are anti-derivatives oF f then F 1 ( x ) F 2 ( x ) = constant independently oF x ; this means that For any two anti-derivatives oF f the graph oF one is just a vertical translation oF the graph oF the other. But no horizontal translation oF the graph oF an anti-derivative oF f will be the graph oF an anti-derivative oF f , nor can
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Version 032 – Exam 3 – gualdani – (56455) 2 a horizontal and vertical translation be the graph of an anti-derivative. This rules out two sets of graphs. Now in each of the the remaining four Fg- ures the dotted and dashed graphs consist of vertical translations of the graph whose line- style is a continuous line. To decide which of these Fgures consists of anti-derivatives of f , therefore, we have to look more carefully at the actual graphs. But calculus ensures that (i) an anti-derivative of f will have a local extremum at the x -intercepts of f . This eliminates two more Fgures since they contains graphs whose local extrema occur at points other than the x -intercepts of f . (ii) An anti-derivative of f is increasing on interval where the graph of f lies above the x -axis, and decreasing where the graph of f lies below the x -axis. Consequently, of the two remaining Fgures only consists entirely of graphs of anti-derivatives of f . keywords: antiderivative, graphical, graph, geometric interpretation 002 10.0 points ±ind f ( x ) on ( π 2 , π 2 ) when f ( x ) = 3 2 cos x + sec 2 x and f ( π 4 ) = 3. 1. f ( x ) = 1 tan x + 3 2 sin x 2. f ( x ) = tan x 3 2 cos x 1 3. f ( x ) = tan x + 3 2 sin x 1 correct 4. f ( x ) = 7 tan x 3 2 cos x 5. f ( x ) = tan x 3 2 sin x + 5 Explanation: The most general anti-derivative of f ( x ) = 3 2 cos x + sec 2 x is f ( x ) = 3 2 sin x + tan x + C with C an arbitrary constant. But if f p π 4 P = 3, then f p π 4 P = 3 + 1 + C = 3 , so C = 1 . Consequently, f ( x ) = tan x + 3 2 sin x 1 .
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This note was uploaded on 08/29/2010 for the course M 46455 taught by Professor Gualdani during the Spring '10 term at University of Texas.

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exam3 kns - Version 032 Exam 3 gualdani (56455) This...

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