This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: silva (jrs4378) – Review 2 – gualdani – (56455) 1 This printout should have 18 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Find the rate of change of q with respect to p when p = 20 q 2 + 5 . 1. dq dp = − 5 q 2 p 2. None of these 3. dq dp = − 10 qp 2 correct 4. dq dp = − 5 qp 2 5. dq dp = − 10 qp Explanation: Differentiating implicitly with respect to p we see that 1 = − 2 q parenleftBig 20 ( q 2 + 5) 2 parenrightBig dq dp , and so dq dp = − ( q 2 + 5) 2 40 q . But q 2 + 5 = 20 p . Consequently, dq dp = − 10 qp 2 . 002 10.0 points A car is given a push down the rollercoaster at Six Flags. If it travels a distance s = 5 t + 4 t 2 in t seconds, find its velocity after 4 seconds. 1. velocity = 40 ft/sec 2. velocity = 39 ft/sec 3. velocity = 37 ft/sec correct 4. velocity = 38 ft/sec 5. velocity = 41 ft/sec Explanation: The velocity of the car after t seconds is given by v ( t ) = ds dt = 5 + 8 t . Consequently, after 4 seconds its velocity = 37 ft/sec . 003 10.0 points If a tank holds 2000 gallons of water, and the water can drain from the tank in 40 min utes, then Torricelli’s Law gives the volume V of water remaining in the tank after t minutes as V = 2000 parenleftbigg 1 − t 40 parenrightbigg 2 . Find the rate at which water is draining from the tank after 10 minutes. 1. rate = 70 gal/min 2. rate = 78 gal/min 3. rate = 75 gal/min correct 4. rate = 77 gal/min 5. rate = 79 gal/min Explanation: silva (jrs4378) – Review 2 – gualdani – (56455) 2 By the Chain Rule, V ′ ( t ) = − 2000 20 parenleftBig 1 − 1 40 t parenrightBig = − 100 parenleftBig 1 − 1 40 t parenrightBig , the negative sign indicating that the volume is decreasing. Consequently, after 10 minutes the water is draining from the tank at a rate = 100 parenleftbigg 1 − 10 40 parenrightbigg = 75 gal / min . 004 10.0 points A point is moving on the graph of xy = 2. When the point is at (2 , 1), its xcoordinate is increasing at a rate of 6 units per second. What is the speed of the ycoordinate at that moment and in which direction is it mov ing? 1. speed = 5 units/sec, increasing y 2. speed = − 5 units/sec, decreasing y 3. speed = 3 units/sec, decreasing y correct 4. speed = − 3 units/sec, decreasing y 5. speed = − 4 units/sec, increasing y 6. speed = 4 units/sec, increasing y Explanation: Provided x, y negationslash = 0, the equation xy = 2 can be written as y = 2 /x . Differentiating implicitly with respect to t we thus see that dy dt = − 2 x 2 dx dt . whenever x negationslash = 0. When x = 2 , dx dt = 6 , therefore, the corresponding rate of change of the ycoordinate is given by dy dt vextendsingle vextendsingle vextendsingle x =2 = − 6 parenleftBig 2 x 2 parenrightBigvextendsingle vextendsingle vextendsingle x =2 = − 3 ....
View
Full Document
 Spring '10
 Gualdani
 Derivative, absolute max. value

Click to edit the document details