PHC4Tests - 15-kg25-kg50 kgms= 0.6k= 0.33520 kgs= 0.40 k=...

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Unformatted text preview: 15-kg25-kg50 kgms= 0.6k= 0.33520 kgs= 0.40 k= 0.35100 N15-kg25-kg1.0 kg1.5 kgk= 010 NslabFblockbetween block and slab: s= 0.80 k= 0.50between slab and floor: s= 0.15 k= 0.1010-kg25-kg1.0 kg2.5 kgk= 010 N20 kgs= 0.45 k= 0.40120 NslabFblockbetween block and slab: s= 0.80 k= 0.50between slab and floor: s= 0.15 k= 0.1010-kg25-kg1.0 kg3.0 kgk= 0.2010 N30 kgs= 0.65 k= 0.50120 NslabFblockween block and slab: = 0.80 k= 0.50ween slab and floor: = 0.15 k= 0.102004 TestsPhysics Honors Test: Chapter 4FORM 1DO NOTWRITE ON THIS TEST. SHOW WORK ON ANSWER SHEET REPORT ALL ANSWERS TO 3 SIGNIFICANT FIGURESVECTOR ANSWERS MUST HAVE MAGNITUDE ANDDIRECTIONUSE SCIENTIFIC NOTATION WHEN APPROPRIATEg= 9.8 m/s2[D]A car with a mass of 1100 kg is being pulled by a tow truck, which exerts a 200 N net force on the car.1)If the car starts at rest, how far has it been pulled during the first 25 s the force is applied?A horizontal 100-N force is applied to a 20-kg box that is initially at rest on the floor. The coefficient of static friction between the box and the floor is 0.40, and the coefficient of kinetic friction between the box and the floor is 0.35.2)What is the acceleration of the box?3)What is the magnitude of the contact force acting on the box?A box is placed on an incline that makes a 40 angle with the horizontal. The coefficient of static friction between the box and the incline is 0.50, and the coefficient of kinetic friction between the box and the incline is 0.35. The box is released from rest.4)What is the acceleration of the box?An 100-kg athlete is performing a vertical leap to test his leg strength. He crouches down, lowering his center of mass by 40 cm, and then jumps, lifting his center of mass upward by 0.90 m after he leaves the ground.5)What force did the athletes legs exert on the ground when he jumped?A 25-kg mass and a 15-kg mass are suspended from either side of a pulley by a massless rope, as shown at right. Assume that the pulley is massless and frictionless. The system is released from rest.6)What is the velocity of the 15-kg block after it has moved 10 cm?7)What is the tension in the rope?A 50-kg block is attached to a massless string over a frictionless, massless pulley. The other end of the string is attached to mass m, hanging from the pulley, as shown at right. The block is placed at rest on a 35 incline. The static and kinetic friction coefficients are 0.6 and 0.3, respectively.8)What is the magnitude of the normal force acting on the block?9)What is the minimum possible nonzero acceleration of the system?2005 TestPhysics Honors Test: Chapter 4 VERSION 1DO NOTWRITE ON THIS TEST. SHOW WORK ON ANSWER SHEET. REPORT ALL ANSWERS TO THREESIGNIFICANT FIGURES. VECTOR ANSWERS MUST HAVE MAGNITUDE ANDDIRECTION. USE SCIENTIFIC NOTATION WHEN APPROPRIATE....
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PHC4Tests - 15-kg25-kg50 kgms= 0.6k= 0.33520 kgs= 0.40 k=...

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