Physics AP Test: Chapters 27 and 28 Form 1 dq i dt = dR dx A ρ = V R i = P iV = 2 P i R = 2 V P R = i R R = ∑ 1 1 i R R = ∑ i C C = ∑ 1 1 i C C = ∑ ( 29 1 t RC q C e ε-=-t RC o q q e-= The circuit at right is made up of an ideal 10-V battery and seven identical 10-Ω light bulbs. 1) What is the equivalent resistance of this circuit? 2) What current flows through point A? 3) What is the voltage between the positive terminal of the battery and point A? 4) Resistor R 1 only is changed so that the power used by R 1 is maximized. Use calculus to determine its new resistance. A wire of length l = 2.0 meters is made of a material of resistivity = 0.75 Ω ·m and is shaped like a truncated cone. The radius of the left end is 0.23 meters, while the radius of the right end is 0.03 meters. 5) What is the resistance of the wire? The circuit at right is made up of resistors R 1 = 5 Ω , R 2 = 10 Ω , R 3 = 15 Ω , and R 4 = R 5 = 20 Ω ; battery #1 of 20 V; and ideal
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This note was uploaded on 08/29/2010 for the course PHYS 45925 taught by Professor Ramesh during the Spring '10 term at Berkeley.