Charged Spherical Conductor - by E=k e Q/R 2 Conductors...

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Dr. Chang Charged Spherical Conductor with Radius R and Total Charge Q Inside the Conductor No charge there as all excess charges reside on the conductor’s surface E=0 everywhere inside. Explained by applying Gauss’s Law V not zero inside. Every point inside the conductor has the same electric potential equal to that at the conductor’s surface (V=k e Q/R), resulting in V=0 and consistent with E =0 inside. Q Δ determines the + sign for V. At the Conductor’s Surface Q uniformly distributed on the surface giving a surface charge density = Q/4 R σ π 2 Electric field perpendicular to the surface with a magnitude given
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Unformatted text preview: by E=k e Q/R 2 Conductors surface an Equipotential surface. V=k e Q/R. Hence V=0 on the surface and that is also why E field has no component on the surface Outside the Conductor Charged spherical conductor treated like a point charge Q located at center E= k e Q/r 2 where r is the radial distance from the center of the sphere and r>R Direction of E is radially outward for +Q and radially inward for Q V=k e Q/r where r > R, forming spherical Equipotential surfaces of radius r Important to see plots of E versus r (Serway Fig.24-11) and V versus r r (Shown in class)...
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Charged Spherical Conductor - by E=k e Q/R 2 Conductors...

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