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Unformatted text preview: by E=k e Q/R 2 Conductors surface an Equipotential surface. V=k e Q/R. Hence V=0 on the surface and that is also why E field has no component on the surface Outside the Conductor Charged spherical conductor treated like a point charge Q located at center E= k e Q/r 2 where r is the radial distance from the center of the sphere and r>R Direction of E is radially outward for +Q and radially inward for Q V=k e Q/r where r > R, forming spherical Equipotential surfaces of radius r Important to see plots of E versus r (Serway Fig.24-11) and V versus r r (Shown in class)...
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