statics hw week 7 - 4.9 REDUCTION OF A SIMPLE DISTRIBUTED...

Info iconThis preview shows pages 1–10. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 4.9 REDUCTION OF A SIMPLE DISTRIBUTED LOADING ’l 91 "if Wind has blown sand over a platform such that 4—154. Replace the distributed loading with an equivalent intensity of the load can be approximated by the resultant force, and- specify its location on the beam ‘ n w = (0.5x3) N/ m. Simplify this distributed loading measured from point A. an equivalent resultant force and specify its magnitude location measured from A. w = (0.5%) N/m Prob. 4—154 Prob. 4~152 '3. Wet concrete exerts a pressure distribution along 5. Replace the loading by an equivalent resultant wall of the form. Determine the resultant force of this ‘féfi'ce and couple moment at point A. 'bution and specify the height h Where the bracing strut d be placed so that it lies through the line of action of resultant force. The wall has a Width of 5 In. *4—156. Replace the loading by an equivalent resultant force and couple moment acting at point B. Prob. 4453 Probs. dI~~~155If156 :1]! problem solutions must include on FBD. 5—11. Determine the normal reactions at A and B in Prob.5—1. *5—12. Determine the tension in the cord and the horizontal and vertical components of reaction at support A of the beam in Prob. 5—4. 05—13. Determine the horizontal and vertical components of reaction at C and the tension in the cable AB for the fuss in Prob. 5—5. 5—14. Determine the horizontal and vertical components reaction at A and the tension in cable BC on the boom in Prob. 5—6. 5-15. Determine the horizontal and vertical components of reaction at A and the normal reaction at B on the manner wrench in Prob. 5~7. “5—16. Determine the normal reactions at A and B and the three in link CD acting on the member in Prob. 5—8. 05—17. Determine the normal reactions at the points of contact at A, B, and C of the bar in Prob. 5—9. 5—18. Determine the horizontal and vertical components of reaction at pin C and the force in the pawl of the winch in Prob. 5—10. 5—1.9. Compare the force exerted on the toe and heel of a :D-lb woman when she is wearing regular shoes and afietto heels. Assume all her weight is placed on one foot and the reactions occur at points A and B as shown. 120 lb 1, 0.75 in. 3.75 in. Prob. 5—19 5.4 Two- AND THREE—FORCE MEMBERS 22 7 *5—20. The train car has a weight of 24 000 lb and a center of gravity at G. It is suspended from its front and rear on the track by six tires located at A. B, and C. Determine the normal reactions on these tires if the track is assumed to be a smooth surface and an equal portion of the load is supported at both the front and rear tires. Prob. 5—20 0541. Determine the horizontal and vertical components of reaction at the pin A and the tension developed in cable BC used to support the steel frame. Isfiiw ,s-axfiK Prob. 5—21 99—5 "10-11! 175—5 “1011] 1—111 {Zn-'1“ 1119919911,; ' ' gammy. \ fi'fik‘?“ W “ix 1; 2 'éa '39 112 959111 10 1911199 p119 31/1 90 19111119111 9111 110 9 39d 10 3512111 1; 31311 1u00q 9111 31291911111 ‘39 112 $512111 10 1911199 pm; 111001113 9111 113 99101 1121111011 9111191113 V 111d 9111 11? 11011929110 in go 3512111 13 S1211 911919 9111 11111119110 1011 590]) 9111319 9111 91119110d11109 1139111911 13119 1121110211011 9111 91111111919q '75—; 11:11] OS 9 9181112 1110011 1111111111111“ 9111 91111111919p ‘31/11 5 81 1391111 9c; 01 p901 9111 11 '911201 93191 31111111 119111111 811111111119119 111011 911919 9111 92111111315 01 139311 9112 £1 19119 V 31933111110 99—91 SEWES .sqm‘l S€“S "101d '3 19 110119991 10 s1119110d11109 129111911 pue 1121110211011 31.111711011991109 9111 111113 1 9911121911: 9111191101112 11111119119111 s11 911111119191) ‘0 113 13911290199911110 1911199 9111111211 ‘fiw z 10 3913111 12 $1211 p901 9111 11 N11 017 10 110151191 11111111111911! 12 13119191111111 11129 p01 9111 ‘gV p01 131112 3 1113 111d 9 Kq p9110ddns s1 911919 c111 9111 159—5. '111 g : 1 11911111 9111219 9111 98129 31111101 m K113119119 9111 put»: 91/ 19111119111 10 110 51V 1301 111 139110191191) 99101 9111 pug 3 111121 9111113 1101191291 1) 11131191911191111111919Q‘UM0113 $12 11291111s1gv110 11011t1q1ns1p 10 s1u9u0d11109 1139111911 131113 1121110211011 9111 911111119191) ‘9 111 I 91nss91d 9111 ‘p9p901 11911111110011 111001115 9113 110 5189.1 119111111 199112901 5312111 10 1911199 511 1111111 31/11 z 10 3512111 12 51211 13901 911111 1 3V 19q1119111 9111 £11 p9110ddns 51 11021191111311 9111 '59—; ‘31; p01 11111: 3112 111d 12 Kq p9110ddns 31 9111919 (1119111 'zg—§* ' 100g Glala 1’ do wnlaamnog g HEILcWHj ng a5-n-——t—-- — 05—37. The wooden plank resting between the buildings deflects slightly when it supports the 50-kg boy. This deflection causes a triangular distribution of load at its ends, having maximum intensities of wA and WE. Determine WA and 1423, each measured in N/m, when the boy is standing 3 m from one end as shown. Neglect the mass of the plank. Prob. 5—37 5—33. Spring CD remains in the horizontal position at all times due to the roller at D. If the spring is unstretched when 9 = 0° and the bracket achieves its equilibrium 'position when 6 = 30°, determine the stiffness k of the Spring and the horizontal and vertical components of reaction at pin A. 5—39. Spring CD remains in the horizontal position at all times due to the roller at D. If the spring is unstretched when 6 = 0° and the stiffness is k 3 1.5 kN/m, determine the smallest angle 9 for equilibrium and the horizontal and vertical components of reaction at pin A. 5.4 Two- AND THREE-FORCE MEMBERS 231 *5—40. The platform assembly has a weight of 250 lb and center of gravity at G. If it is intended to support a maximum load of 400 lb placed at point G2, determine the smallest counterweight W that should be placed at B in order to prevent the platform from tipping over. 1 ft Prob. 5—40 05—41. Determine the horizontal and vertical components of reaction at the pin A and the reaction of the smooth collar B on the rod. Probs. 5—38139 Prob. 5—41 917/917'5 'Sqo-IJ EV‘S 'qo-ld 1111110113 1101113011 9111 111 s; 111000 511 11911111 11111119110 01 9111319 9111 3111311120 11101111111 p91111 9q 1113:) 112111 11111119 9111 10 111319111 139311319111 9111111191939 112 1511211113 10 1911199 12 1111111 q1 oogz 10111319111 11—1101 12 9111211 19111113 9111 [3118 9111319 10011 9111 '917—5 1111110115 1101119011 9111111 511110011 9111 11911111 51 11; 319911111 9111 111011 1302 V .112 31991111 9111 111011 110 110119991 1121111011 9111 911111119191) ‘111n1p c11—009 9111 1111 01 p91111b91 s1 91112.10 9111 11 '9 12 511111218 10 1911199 12 1111111 01 oogz 10 111110113 11011190119111111511101 9111 11911111 9111120 9111111901019111 11131911 112101 12 9A1211 19111113 9111 131113 9111319 10011 9111 '517—9. 9u11111919q111g1 10111319111 12 81311 31771301 11110111111 911L 'gp—g [717—5 "‘19-‘11 zv-s "10M N 00S ’we9q 139111119 ‘qg p01 3110112 9p11s 01 1391101112 s11nq‘gV 911110 51 1951901 9111112 1101191291 9111111112 V 111d 9111112 9910110 p01 9111 01 1391111 31 1121109 9111 1301 9111 110 51 1131109 111001115 31119110d11100 1130111911 p119 1131110211011 9111 91111111919q 1717—51,: 9111 p119 V 19110110 31101191291 110ddns 9111 91111111919q 711—5 ACIDS CIIDIH V :IO WRIHEH'IIHDEI g HEIidVHQ If; U] l u” u uu' mmmmwmmmmmwmwmhfiwfismw:mmrmmmmum ammu-swm—xmwam—s; mamqmnwm-smam « fiupeeq 12111110! 9181118 'SQIdLLI’BXQ if} rd :X 1w 9111 993 91911119319 p9110ddns s1 Apoq 9111 11 peqdde ? _ 1011 [(1112191193 9113 91113111001 91dn00 sq; :910N 1112115 9111 51““:‘1; 01 1131001pued13d 108 [[0ng Siluauoduloa 1u3m0w-01d1100 " 01m, p112 93101 0111 9119, 3110110291 311; ‘sumoumm 11103 *2“ (9) 193305 puB {[Eq 'smguodmoo 9010;!r 11211131121091 091111 0113 81101101331 0111‘ 'sumouxun 0:;qu 191101 '13121u03101u10d 911119 9313'an 21111 01121113111119de 81312 qomm 9010; e 51 uouaem sq; 1211011111111 9110 110ddns 901911115 111001115 101211103 10 1u10d 91.11 11; soeyns 9111 0111211101puad1sd 31312 11311111 9010; '8 31 1101101291 sq; ‘umoumm 9110 '91q130 911110 1101109111) umoml 9111 U1 IQQIIIQIH 9111111011 \._ :\ 512112 51012 11:)ng 93101 E 31 1101131301 aql 'umouqun auo ' (I) sumou u 0.16 um uogaeaa uomeuuo 0‘3de )i {H C! N . 3} .L 1009 01913 v :IO wmasnmog 9 HELdVHj 393 5.5 FREE-BODY DIAGRAMS 2 39 Types of Connection Reaction Number of Unknowns 6 ( ) M2 .fi / ' F Five unknowns. The reactions are two force and three . .. . ‘ xii-“‘4‘ M couple—moment components. Note: The couple moments _ Mx " are generally not applied if the body is supported single journal bearing 1’ Ft “ elsewhere. See the examples. with square shaft Five unknowns. The reactions are three force and two couple-moment components. Note: The couple moments are generally not applied if the body is supported elsewhere. See the examples. single thrust bearing Five unknowns. The reactions are three force and two couple-moment components. Note: The couple moments are generally not applied if the body is supported elsewhere. See the examples. single smooth pin (9) Five unknowns. The reactions are three force and two couple-moment components. Note: The couple moments are generally not applied if the body is supported elsewhere. See the examples. single hinge M). (10) Six unknowns. The reactions are three force and three couple—moment components. fixed support All problem solutions must include an FBD. 5—63. The cart supports the uniform crate having a mass of 85 kg. Determine the vertical reactions on the three casters at A, B, and C. The caster at B is not shown. Neglect the mass of the cart. Prob. 5—63 *5—64. The pole for a power line is subjected to the two cable forces of 60 lb, each force lying in a plane parallel to the x— y plane. If the tension in the guy wire AB is 80 lb, determine the x, y, 2 components of reactiorr at the fixed base of the pole, 0. 60 1b Prob. 5—64 5.7 CONSTRAINTS AND STATsCAt DETERMINACY 25 3 lI5-—65. If P = 6 kN,x = 0.75 m and y : 1 m, determine the tension developed in cables AB, CD, and EF. Neglect the weight of the plate. 5-456. Determine the location A: and y of the point of application of force P so that the tension developed in cables AB, CD, and EF is the same. Neglect the weight of the plate. N Probs. 5-6966 5—67. Due to an unequal distribution of fuel in the wing tanks, the centers of gravity for the airplane fuselage A and wings B and C are located as shown. If these components have weights WA = 45 000 lb, W3 = 80001b, and WC 2 60001b, determine the normal reactions of the wheels D, E, and F on the ground. Prob. 5—67 5.7 CONSTRAINTS AND STATICAL DETERMINACY 2 5 5 *5—72. Determine the components of reaction acting at the 5-74. If the load has a weight of 2001b, determine the x, y, smooth journal bearings A, B, and C. z components of reaction at the ball-and-socket jointA and the tensiOn in each of the wires. Prob. 5-72 Prob. 5-74 05—73_ Determine the force components acting on the ball- 5’75. the CflblC can 136 SUbjeCted to a maximum [GHSiOIl and—socket at A, the reaction at the roller B and the tension of 300 lb, determine the maximum force F which may be on the cord CD needed for equilibrium of the quarter applied to thfi Plate. Compute the I, y, z COrflpDnents of circular plate. reaction at the hinge A for this loading. Prob. 5—73 Prob. 5—75 ,'_‘ panunuoa mwmmmummmmm!Hmmmmmmmtmihwrmwmmww , p01 Ipoouis no 1121103 01 psisauuoa uid JquQLU ‘pOJ sq} 01 lelnorpuadlad 9 31312 qoiqm 9310} u s; nonaeel oql 'umouqun suO GOEflflS EHIJOBIHOU quOlflS 13211103 in JHlOd 91.11 112 ooeglns 91.1101 inmatpuadlsd l0 fare S132 qoiqm 9010; 12 SI uouoeei eql 'umounun 9H0 Jails/01 daemon J0 1uyod mp 12 ootqms 91.11 01 mlnaipuadiod $132 Ipnpn 3310;13 3} Homeox oqL 'umounun 9H0 1015 qlooms pouguoo Ln uid 10 191101 .1015 911101 mlnoipuodlod 9 J W J 9 3102 qoiqm 9310; 17. s! Homeol oql 'umouilun 9110 «if: m jg ‘ r _ I Y Ex n ‘ (17) :l 101211100 10 mod am 112 SOBJmS eq101m1naipuedlod 51013 qoiqm 3010; 13 3! [10931231 SILL 'umounun euO / mm 9111 J0 sixe’em Burma sine qoiqm 9010; e 91 Houses: sq; umouqun euo ‘omeo 9111 JD nonosnp sq: ui xeqvueuu 9L1]. 1110.1; Ame J 9132 quiqm 9310; uoisuel 2 91 Houses; eql 'umounun euo 9 sumouqun in JeqmnN uonoeey uonaeuuog to sad/("L mog elem V AC) lAflIaEH'lnDEI g HSLdVHj zoz 5.2 FREE-BODY DIAGRAMS Types of Connection Reaction Number of Unknowns TWO unknowns. The reactions are two components of force, or the magnitude and direction dz of the resultant force Note that (15 and 9 are not necessarily equal [usually not, unless the rod shown is a link as in (2)]. \ [h pin or hinge TWO unknowns. The reactions are the couple moment and the force which acts perpendicular to the rod. ' fixed connected —- on smooth rod F Three unknowns. The reactions are the couple moment 4> g and the two force components, or the couple moment and M the magnitude and direction 4; of the resultant force F! g g or M -v support ...
View Full Document

This note was uploaded on 08/29/2010 for the course EGN 3311 taught by Professor Nohra during the Fall '08 term at University of South Florida - Tampa.

Page1 / 10

statics hw week 7 - 4.9 REDUCTION OF A SIMPLE DISTRIBUTED...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online