GE310HW#1solution - 3—27 Determine the forces in members...

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Unformatted text preview: 3—27. Determine the forces in members IH, AH. and BC of the truss. State if the members are in tension or compression. 10kN IOkN SkN 5m—‘L_5mfil"’5m“’l‘—-5m . Prob. 3-27 (mm = 0; 5,,(5 m) — 10m (5 m) = 0 F,” = 101;»: (C) Ans C+zMy=0; 55(5m)+10kN(5m)—14kN(10m) =0 15w = 18kN m Ans F21; = o; 14kN — 10 kN _— fiHsin2656° = E,” = 8.94kN (C) Ans HWl ANsTs soln Reaction Forces luE FOLLOWING X,Y,Z SOLUTIONS ARE IN GLOBAL COORDINATES NODE FX FY .111«___1——0711164E514~ 14 000 . .um-uwmmmm_~~ 5 14.000 TOTAL VALUES VALUE 0.17764E—l4 28.000 Member Forces STAT CURRENT ELEM MEMBERFO 1 18.000 2 18 000 3 18.000 4 18 000 5 0.0000 6 —14.142 7 —8.9443 8' —8.9443 9 —14.142 10 0.0000 11 0.55077E—14 12 —10.000 13 —10.000 14 —O.55077E—14 15 10.000 16 8.0000 17 10.000 MINIMUM VALUES ELEM VALUE 6 -l4.l42 MAXIMUM VALUES ELEM VALUE 2 18.000 Joint Displacements THE FOLLOWING DEGREE OF FREEDOM RESULTS ARE IN GLOBAL COORDINATES Z O U m H OkOOJQGNUWerMI—l OOOOOOOOO 'Ux UY 0.0000 0.0000 .35433E—03-0.l6591E—02 .70866E—03—0.24551E—02 .10630E—02—0.l659lE—02 .14173E—02 0.0000 .90551E-03 0.0000 .90551E—03—0.l4623E—02 .70866E—03—0.22977E—02 .51181E—03—0.l4623E—02 .51181E—03 0.0000 MAXIMUM ABSOLUTE VALUES NODE VALUE 5 3 0.14173E—02-0.24551E-02 ...
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This note was uploaded on 08/31/2010 for the course IESE GE 310 taught by Professor Kim during the Fall '09 term at University of Illinois at Urbana–Champaign.

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GE310HW#1solution - 3—27 Determine the forces in members...

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