solutions4 - 5.4 Air flows steadily between two cross...

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Unformatted text preview: 5.4 Air flows steadily between two cross sections in a long. straight section of 0.1-m inside-diameter pipe. The static tem- Section (1) Section (2) perature and pressure at each section are Indicated in Fig. P5.4. 77 P _ 45 RP ( b ) If the average air velocity at section (1) is 205 m/s, determine 1;: 26; K3 (am) g2 ; 240 K3 a s the average air velocity at section (2). V1 = 205 "V5 2 fl FiGURE P5.4 7h}: armé/JI'S III JIM/Var 79 7%.: One d; firamp/e 5.2 . For Sfeaa’y 100w Ae/weem isccfions (I) and{2) m2: Ml 0r __ __ 6A2K~://0A/l// 76645 V: 5151 ’v; m Z ’3 A; Assam/n} 7am; under fire com/i790”: 0/ f4}; froé/em) m} fiehaue; a; an ideal gas We use #26 [deal ya; cgum‘fon 01‘ 57"4/6 $3) 75 961‘ A?! 7.: i1: 1’ (2} ' ’02 5 7: Comé/nlhj €35. / and .7. and chew/Xvi 1652421 14, =4; we gei- \7 = ,9 7’1 V, = [7? Medal” 17(24OK) (205 2 I; 7/ [’75 Hams )](258/<) V: 3/4 93 :2 5 COflfYD/ vo [u "it. 5. Ci A water jet pump (see Fig. 135.9) in- volves a jet cross section area of 0.01 ml, and a jet velocity of 30 m/s. The jet is surrounded by entrained water. The total cross section area as- sociated with the jet and entrained streams is 0.075 m2. These two fluid streams leave the pump thoroughly mixed with an average velocity of 6 .m/sthrough a cross section area of 0.075 m2. 7 FIGURE P5. q Determine the pumping rate (i.e., the entrained fluid fiowrate) involved in liters/s. For sread/V in campressib/c f/ow 791/0149}; +146. com‘rv/ l/o/ume [(6 0. 075 m“) — (30 rana Olm?](000:§j 5.14 Oil having a specific gravity of 0.9 is pumped as SeCth" (1) illustrated in Fig. P5.l4 with a water jet pump (see Video V3.6). The water volume flowrate is 2 m3/s. The water and oil mix- ture has an average specific gravity of 0.95. Calculate the rate, Section (3) in "13/5, at which the pump moves on. Water wéater Q1 = an_d Qm3/s “oiliIX Section (2) (50 = 0.95) on ($0 = 0.9) For 5+eady FIGURE P5.1'+ .. . = m ml+ m1 3 0r flq+gQL=6Qs (I) [4/50, S‘lhce. Me der and ai/ may ée cam/‘dmd Mam/,ex/é/e a, + Q2 = 623 (Z) Comé/n/nj E35. / arm/Z we gef me, + g 92 = g/a,+az) 0” Q,+ SGZQ - 563(QIJ' Q2) and Q _ a] ( l—— 563) z _ 5633 ~ 561 TAUS 3 \ Q = (1%)(/’0'%/ _ 200333 0.?5» 0.90 5 5— /3 5.22 How long would it take to fill a cylin- drical shaped swimming pool having a diameter ofIOm to a depth of 1.5 m with water from a garden hose if the flowrate is 1.0 liter/s? dEFUrmi/lj comLm I V0 lame 90m app/{66129054 02‘ 7%6 conservaé’om 0/ mas: pr/nc/p/c 74; 7%e, can/rv/ va/ume canfiz/h/hj wa/a» on/y a5 Skown 1;, +144: Figure we have ‘ 5.25 A hypodermic syringe (see Fig. P515) ‘ is used to apply a vaccine. If the plunger is moved forward at the steady rate of 20 mm/s and if vac- cine leaks pass the plunger at 0.1 of the volume flowrate out the needle opening, calculate the average velocity of the needle exit flow. The in- side diameters of the syringe and the needle are 20 mm and 0.7 mm. FIGURE P515 (15059 a deémky cam‘m/ Vo/qme and f/ve convert/52242” of Mas; pm'vc/p/e. (53. 51/7) 45 au/Myed I}: Examp/e .57 5’) WC 667%”); (Ice 53. 2 of Example 538 ) (I) “flA/K’ + /0Q2 f flgleak g 0 5/hce /0= caanan 62/6“ = (2/ Q2 and CZ=A2V2 We, aé/znia W 53.1 // = Allé ar 2 I; = (£2 ) i =/fli)__lé (20mm) (Zam’n/s z 1/ z /./ a m, * , /000mm and c1, (7 2 f /) K _ V = #755 1’14 2 5 5-2 5.3! 5.3 I A nozzle is attached to a vertical pipe and discharges water into the atmosphere as shown in Fig. P5.3l. When the discharge is 0.1 m3/s, the gage pressure at the flange is 40 kPa. Determine the vertical component of the anchoring force re- quired to hold the nozzle in place. The nozzle has a weight of 200 N, and the volume of water in the nozzle is 0.012 m3. Is the anchoring force directed upward or downward? I FIGURE P5.3i The analysis fleet/153 7% me Ja/ufi‘ah m” 7%}; praé/em is ward/aw 7‘0 {fie one auHMed “a Exam/9k, 5/0. included [n file cam’ro/ Vat/W are )1: nag/c and 17:: Wd/W H"! We non/o all" In insylnnl. fipfl'wfi'on 07‘ 1%: mam 0r 2- olt'reofi'on componem" 0% fl", Mica,» momem‘um azuafim (53. 5-22) 7‘0 We flow film?!» “is VOA-(MCI [adds 7‘0 Ofigic — a o - 0 _ - — - d I mfgsm3o—K)-/7AI 1:? vi; 1’th zALs-mw () 4?’ ' 'n ‘1. 2) eizP‘AI-Vlg-ML—m/strza C 07 6? I A/sa we naf fladf “3 £71 ' 14. 77w; 5;. z kme: ’ W {743, Q/ézsdyzatfi F 2 F; ’4: ” r) ‘- W W K AZ fl: AZ’ or A/ aoo F“ I zoo/v , / _,_ l __ 0.02M ’ a? ‘ m7? Pa fipa){ ) _ (“0,2 m2)(7.g ZgJ/Maofi/‘fi- ? 3 ‘ 3 *[777— 0.0/21 IE1 0.0!?— , . 0.01:5: "13 .5 4m" 5m 30— _. 1 0'0/ m7- F; : 800M - ZOOM—117.6N— 0N = 4-82 N dOanard ————- 5-30 A/sa we naf fladf “3 £71 ' 14. 77w; 5;. z kme: ’ W {743, Q/ézsdyzatfi F 2 F; ’4: ” r) ‘- W W K AZ fl: AZ’ or A/ aoo F“ I zoo/v , / _,_ l __ 0.02M ’ a? ‘ m7? Pa fipa){ ) _ (“0,2 m2)(7.g ZgJ/Maofi/‘fi- ? 3 ‘ 3 *[777— 0.0/21 IE1 0.0!?— , . 0.01:5: "13 .5 4m" 5m 30— _. 1 0'0/ m7- F; : 800M - ZOOM—117.6N— 0N = 4-82 N dOanard ————- 5-30 5.36 5.36 Video V9.7 and Fig. P536 is a result of water pumped through the vehicle and exiting as a high-speed water jet. For the conditions shown in the figure, what flowrate is needed to produce a 300 lb thrust? Assume the inlet and out- let jets of water are free jets. The thrust developed to propel the jet ski shown in 3.5 in. diamter ’ outlet let I FIGURE P536 For #78 confrol Vo/Ume .im/I'cafeal Me x~ component‘ of the women/um eyuah‘on ju (27')? 0M =25 becomes CS confro/ safface (l4 cos3o°)€(-V,)/),+ V2 p(+Vz)/42 = Rx where we hat/e assumed 41ml 2W0 on 7% amt/re confro/ Jar/ace and find the exit/I79 Wafer jetl is barizanial. lit/[7’10 m = (WV, =94sz E71!) becomes Rx=l7'7(V2’V/6059) =€l/114,(V2'V,cas30°) (1) 9/50, I4, W; = #1 V2 5a fbaf HIV: 7.51.0.1 4’: "‘ = : . ) V2 AZ g{3'5m)z Vi 2 60 VI (2 By comb/fling £75. (I) and (Z): Rx = prfll (2,60'50330') 0r ‘& V = 300 z 22 I /.9‘/-ii’9£ 3—5—5!‘ 240—50530”) ' S H3 M 7771/: / Q =’4 M = (figwymgpawg 5’37 ...
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solutions4 - 5.4 Air flows steadily between two cross...

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