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s35 - P35.4(a For the light beam to make it through both...

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P35.4 (a) For the light beam to make it through both slots, the time for the light to travel the distance d must equal the time for the disk to rotate through the angle θ , if c is the speed of light, d c θ ω = , so d c ω θ = . (b) We are given that , 2.50 m d = 4 1.00 rad 2.91 10 rad 60.0 180 π θ ° = = × ° , 4 2 rad 5555 revs 3.49 10 rad s 1.00 rev π ω = = × ( ) ( ) 4 8 4 2.50 m 3.49 10 rad s 3.00 10 m s 300 Mm s 2.91 10 rad d c ω θ × = = = × = × P35.8 The incident light reaches the left-hand mirror at distance ( ) 1.00 m tan5.00 0.0875 m ° = above its bottom edge. The reflected light first reaches the right-hand mirror at height . ( ) 20.0875 m 0.175 m = It bounces between the mirrors with this distance between points of contact with either. Since 1.00 m 5.72 0.175 m = Mirror Mirror reflected beam 1.00 m 5.00° 1.00 m FIG. P35.8 the light reflects five times from the right-hand mirror and six times from the left . P35.15 (a) 1 1 2 sin sin n n θ θ = 2 1.00sin30.0 sin19.24 1.52 n n ° = ° = (c) 8 14 7 3.00 10 m s 4.74 10 Hz 6.328 10 m c f λ × = = = × × in air and in syrup.
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