s35 - P35.4 (a) For the light beam to make it through both...

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P35.4 (a) For the light beam to make it through both slots, the time for the light to travel the distance d must equal the time for the disk to rotate through the angle θ , if c is the speed of light, d c ω = , so d c = . (b) We are given that , 2.50 m d = 4 1.00 rad 2.91 10 rad 60. 01 8 0 π ° ⎛⎞ == × ⎜⎟ ⎝⎠ ° , 4 2 rad 5 555 rev s 3.49 10 rad s 1.00 rev × () 4 8 4 2.50 m3 . 49 10 rad s 3.00 10 m s 300 M m s d c × = × = × P35.8 The incident light reaches the left-hand mirror at distance 1.00 mtan 5.00 0.087 5 m °= above its bottom edge. The reflected light first reaches the right-hand mirror at height . 20.087 5 m0 . 175 m = It bounces between the mirrors with this distance between points of contact with either. Since 1.00 m 5.72 0.175 m = Mirror Mirror reflected beam 1.00 m 5.00° 1.00 m FIG. P35.8 the light reflects five times from the right-h an d mirror and six times from the left . P35.15 (a) 11 2 si ns i n nn θθ = 2 1.00sin30. 0s i n19.24 1.52 n n ° = (c) 8 14 7 4.74 10 Hz 6.328 10 m c f λ × = × × in air and in syrup.
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This note was uploaded on 08/31/2010 for the course PHYSICS 7E taught by Professor Staff during the Fall '08 term at UC Irvine.

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s35 - P35.4 (a) For the light beam to make it through both...

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